How many grams of v203 would you need to have 7.56e11 atoms of oxygen?
To determine the grams of V2O3 needed, we first find the number of moles of oxygen atoms in 7.56e11 atoms. Then, using the molar ratio in V2O3 (2 moles of oxygen for every mole of V2O3), we find the moles of V2O3. Finally, we convert moles to grams using the molar mass of V2O3.