Not sure I understand your question, please clarify
Center of mass
10-100 usd
gatlin
Use conservation of linear momentum. Before firing the bullet the total momentum was zero (assuming you were not moving), therefore, after firing the bullet, the total momentum must needs also be zero. Therefore, after the shot, m1v1 + m2v2 = 0, where m1 and v1 correspond to the pistol, and m2 and v2 correspond to the bullet.
No published sn data
The name of the star is "Pistol Star". According to Wikipedia, it has 27.5 times the mass of our Sun, and 306 times the radius of our Sun. Due to observational difficulties, I would expect both numbers to be estimates.
The exact value of an Iver Johnson 22 caliber target pistol actually is dependent upon a number of factors. Some of these factors include the age and condition of the pistol.
100 at the outside
That is Chicopee Falls, MASS, U. S. A.
there is no 45 pistol, however there is a 44 pistol. the 44 pistol can be found as random loot or off the corpse of someone with a 44 pistol.
Either to kill with a pistol or hit said target with a pistol. It basically means use a pistol.
Momentum before = momentum after. Since there was no movement before, momentum before = 0 If you think of the bullet as forward/positive momentum and the gun as backward/negative momentum then the momentum of the bullet plus the momentum of the gun =0 and therefore the momentum of the bullet = the momentum if the gun. momentum = mass x velocity P=m/v 20gx150m/s = 2000g (2kg) x velocity 3000 = 2000v 3000 / 2000 = v v = 1.5m/s