151553
4 offsprings
The offspring will likely be a mix of black and white feathers, as erminette coloring is a pattern that combines both black and white. The specific distribution of colors will depend on the genetics of the parent chickens.
The black guinea pig is likely heterozygous (Bb) for coat color, while the white guinea pig is homozygous recessive (bb). The black guinea pig passes on a black allele to all offspring, resulting in 4 black (Bb) and 2 white (bb) offspring.
The white eyed flies that resulted from the crossing of the red-eye flies were all male as the gene involved was on the X chromosome. The X chromosome is the male chromosome.
When black dominates white in certain rat species, the genotype of the black rat would be homozygous dominant (BB), while the genotype of the white rat would be homozygous recessive (bb). When two hybrid black rats (Bb) are crossed, the possible genotypes of their offspring would be 25% homozygous dominant (BB), 50% hybrid (Bb), and 25% homozygous recessive (bb).
1:2:1
4 offsprings
If you cross a red 4 O'clock with a white 4 O'clock, the phenotype will be pink This is because red has incomplete dominance over white, so the alleles blend. If yellow is crossed with white, the flowers are always yellow.
If red color is dominant, (RR) and white is recessive, (rr) then crossing a homozygous red plant with a homozygous white plant will produce 100% red offspring. This is the F1 generation. These F1 offspring will be 100% heterozygous (Rr). Subsequent crosses of these offspring in the second generation (F2) will produce 75% red and 25% white offspring phenotypically (the visual appearance of the color, The genotype ratio will 1 RR: 2 Rr:1rr with percentages of 25% homozygous red 50% heterozygous red and 25% homozygous white.
The offspring will likely be a mix of black and white feathers, as erminette coloring is a pattern that combines both black and white. The specific distribution of colors will depend on the genetics of the parent chickens.
The address of the Feathered Hearts is: 17214 E Bob White Rd, Mayer, AZ 86333-4228
Your F1 generation has 0% of short, white plants. Anything crossed with TtRR wil have at least one R = red. Possible alleles of plant ttRr: tR and tr (on the horizontal) Possible alleles of plant TtRR: TR and tR (on the vertical) Using a Punnett's Square: tR tr TR TtRR TtRr tR ttRR ttRr TtRR = Tall, Red TtRr = Tall, Red ttRR = Short, Red ttRr = Short, Red So, as you can see, all of the possibilities have at least one R, so they will all be red, since R is dominant.
If both parent plants are white-flowered, then all of the 1000 offspring would be expected to have white flowers. This is because the white flower trait is a result of a homozygous genotype, and both parents would pass on the white flower allele to their offspring.
The black guinea pig is likely heterozygous (Bb) for coat color, while the white guinea pig is homozygous recessive (bb). The black guinea pig passes on a black allele to all offspring, resulting in 4 black (Bb) and 2 white (bb) offspring.
The genotype for a white-eyed male fruit fly is X^wY, where X is the sex chromosome and Y is the Y chromosome. The w denotes the gene for white eyes located on the X chromosome. This genotype indicates that the male fruit fly has a white-eye phenotype due to the recessive white eye allele.
The white eyed female fruit fly has two recessive traits for eye color. The genotype would be xx for example.
Angel from the X-Men universe has white, feathered wings. :)