The reason is because short tail cats have both genes of a no tail cat and a genes of a long tail cat.
Lets say that a long tail gene is called gene A, and a no tail gene is called gene B.
if both cats have short tails that means both cats have both genes A and B equally. so there is a 50-50 chance that each cat gives either gene to the baby
This means the possible combinations are that one cat gives the baby an A and the other a B, remember that this possibility comes up twice since it doesn't matter which cat gives the A or the B. The other possibilities are that both cats give the kitten an A, or both cats give the kitten a B.
That leaves AB(short tail), BA(short tail), AA(long tail), BB(no tail)
so 25% for no tail, 25% for long tail, and 50% for short tail.
50%
Yes, the offspring has a 50% chance of being polled. The polled gene is dominant over the horned gene, so if the bull does not carry the horned gene, the offspring will not have horns.
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
100% because BB is dominant over bb and all the crosses make Bb
increases genetic diversity, allowing for a better chance of producing offspring with advantageous traits to adapt to the changing environment. It also helps in combating parasites and diseases effectively through recombination of genes.
50/50 chance
50%
A cross between two homozygous parents will form a 100 percent chance of a heterozygous offspring. One homozygous parent must have the dominant allele, and the other must have the recessive allele. So, if the circumstances are correct, these characteristics will make for a 100 percent chance of a heterozygous offspring.
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
There is insufficient information for us to even begin to understand this question. Please edit the question to include more context or relevant information. So the chair has made a rather unhelpful statement. What is the question?
50% of the offspring are female. Gender determination in offspring is typically governed by a 50/50 chance.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
1: If your saying the whole world then it's 0.00153 percent.2:If your saying any random country then there is a 0.45731 percent chance.3:(a)If your talking about a random city(large) then there is a chance of 0.8662... percent chance,(b)random city(medium) then there is a chance of 0.921... percent chance,(c)random city(small) then there is a chance of 0.9992432112 percent chance.4:(a)If you are asking about a neighborhood(large)there is a chance of 1.28436.. percent chance,(b)a neighborhood(medium)there is a chance of 0.134.. percent chance,(c)a neighborhood(small and I mean very small)there is a chance of 0.001112.. percent chance.(Hope you like my answer because it took me a whole day to browse and find it.)
50%, or half. Therefore, there is an equal chance that the offspring will be female.
The chair of the board of directors says, "There is a 50 percent chance this company will earn a profit, a 30 percent chance it will break even, and a 20 percent chance it will lose money next quarter".
If you have a 1 percent chance of doing something, and you have 30 tries, your chance of succeeding is 26 percent, or 1 - (1 - .01)30.
50% chance