BeCl2(aq) + 2NaOH(aq) -> 2NaCl(aq) + Be(OH)2(s)
Be(aq) + 2OH(aq) -> Be(OH)2(s)
Hope this helps!
The answer is 24. NOT 12 + 6, If it weighed 18kg 6 isn't half it's weight. If weight=W W=12+W/2 W-W/2=12 W/2=12 W=24
the answer to 111+112+113=336
it is SEVEN!!!!!!!!!!!!!!!! RAAAAAAAAAAAAAAAAAAAAAAAAAAAAAARGH!!! OMIFUKNGOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! RAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAR it is SEVEN!!!!!!!!!!!!!!!! RAAAAAAAAAAAAAAAAAAAAAAAAAAAAAARGH!!! OMIFUKNGOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! RAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAR
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Zombies don't exist and are fictional, plus they are dead. So, your answer is no.
The net ionic equation for NaOH (sodium hydroxide) in water is: Na⁺ + OH⁻ → NaOH. This represents the dissociation of sodium ion and hydroxide ion to form sodium hydroxide in solution.
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq) Ionic Equation: H+ + ClO4- + Na+ + OH- → H2O + Na+ + ClO4-
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.
The net ionic equation for the reaction between NaOH and HCl is: OH- + H+ --> H2O. This equation represents the formation of water from the combination of hydroxide ions and hydrogen ions. Sodium and chloride ions are spectators in this reaction and are not involved in the formation of the products.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
Ni2+(aq) + SO42-(aq) + 2 Na+(aq) + 2 OH-(aq) ==> Ni(OH)2(s) + 2 Na+(aq) + SO42-(aq), the ionic equation is ; Ni2+(aq) + 2 OH-(aq)==> Ni(OH)2(s)
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
The equation given is correctly balanced, because it contains the same numbers of each kind of atoms in the reactants as in the products.
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)