Let's break this into binary first:
11111111 11111111 11110000 00000000
For a class b network, there are 16 bits available (the right 16 numbers). We see that 4 of those have been borrowed already (they have 1's) so we have 12 left.
The formula to find the maximum number of hosts is 212 - 2 (the 12 comes from the number above).
So, the answer is 4096.
----------------------------------------------------------------------------------------------------------------11 hosts
ANSWER:
This would be a Class B network.
If this is the subnet you have been designated then without subnetting further 8*256=2048 - first and last address will be used by the network so
= Usable host addresses =2046 for this given subnet.
3 bits are borrowed from a class C so the 248 looks like 11111000 in binary, these zeros incremented once for each class C network up until it's (255)11111111 gives you this result 2048
000, 001,010,011,100,101,110,111
For IP 172.0.0.1/21
Range of IP's would look like 172.0.0.1 - 172.0.7.255
I'd advice searching online for a "Subnet Chart" or "Subnet Calculator" to aid you further.
255 per subnet
255-15 = 230
230*255=58650 Devices on that subnet
255.0.0.0The default subnet mask of a class A network is 255.0.0.0
Since this is a class B network you have borrowed 8 bits for subnets. This leaves 8 bits left (1 octet) for clients/workstations. That gives you a maximum of 254 clients per subnet.
254
If this is a default subnet mask, then it would be a class C subnet mask. If you are subnetting a network and this is not the default subnet mask, then it could be either a class A or class B.
Class C network if you are not subnetting.
195.85.8.0 is a class C network. The subnet mask would be 255.255.255.0 and the network address is 195.85.8.0
Since this is a Class C address, the default network mask is 255.255.255.0.Since this is a Class C address, the default network mask is 255.255.255.0.Since this is a Class C address, the default network mask is 255.255.255.0.Since this is a Class C address, the default network mask is 255.255.255.0.
The submask indicates the division between the network id and the host information in an ipV4 address. The default subnet mask indicates the presence of a class A, B, or C based network (the default) without subnetting.
You can borrow 6 bits. Which would create a 255.255.255.252 subnet mask, but this subnet only contains 2 usable IP addresses. 7 bits would be 255.255.255.254, but that subnet is too small to have any use in the real world.
A class C network has a subnet mask of 255.255.255.0 and can have 254 IP addresses, for example from 192.168.0.1-192.168.0.255 A class B network has a subnet mask of 255.255.0.0 and can have 255 X 254 IP addresses, for example from 192.168.0.1 - 192.168.255.255
The maximum number of host bits that can be borrowed from a class A address is 22 (technically you could borrow 23 but the resulting network would be useless). A class A address uses 8 bits for its network address and 24 bits for its host addresses. Class A uses a subnet mask of 255.0.0.0 You can only borrow 22 bits (instead of 24) because a valid network requires 4 addresses: A network address, two host addresses and a broadcast address. These networks would result in 30 bits used for the network address and 2 bits used for the host addresses. These networks use a subnet mask of 255.255.255.252
172.16.0.0. The first ip address within this subnet is 172.16.0.1