If this is a homework related question, you really should consider trying to solve it yourself before looking at this answer. Otherwise, the value of the lesson, and the reinforcement provided by the assignment, will be lost to you.
To calculate the current flow in one element of a parallel circuit, knowing the resistance of each element, consider the net resistance first.
Two resistors in parallel, R1 and R2, have a net resistance of R1R2/(R1+R2). For 50 ohms and 10 ohms, this is 8.333 ohms.
Now, consider the voltage across the resistors. By Ohm's law, voltage is current times resistance. For 12 amps and 8.333 ohms, you get 100 volts.
Now, consider the current through one resistor, By Ohm's law, current is voltage divided by resistance. For 100 volts and 50 ohms, you get 2 amps.
All of that said, now to the easier method...
Resistors in parallel form a current divider, just like resistors in series form a voltage divider. You have two resistors, 10 ohms and 50 ohms, with 12 amps going through them. The current through the 50 ohm resistor is the ratio of the other resistor divided by the sum of the two resistors. This is 12 amps times 10 / (10 + 50), or 12 amps times 1 / 6, or 2 amps.
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
A galvanometer is a type of ammeter an instrument for detecting and measuring electric current. A galvanometer can be converted into ammeter by connecting resistance in parallel with it.
You connect a galvanometer in series with the circuit being measured, because the galvanometer is a form of ammeter, although an extremely sensitive one, and ammeters measure the current in a series circuit.
It is halved. coz voltage=current * resistance
in a parallel circuit resistance decreases increasing the current.
Based on the principle of the D'Arsonval galvanometer, the main function of a multimeter is measuring a circuit's voltage, current, and resistance.
A shunt resistance is a low resistance connected parallel to the galvanometer so that a large portion of current passes through the low resistance and a small fraction of current passes through the galvanometer this saves the galvanometer from damage
Ohms are the unit of measurement for resistance, so an ohmmeter is a device that measures electrical resistance. A galvanometer measures the current flowing through the resistance, so the two are related. To convert a galvanometer into an ohmmeter, one needs an external battery.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
A Galvanometer can be used to detect the presence of current in a circuit. An ammeter can be used to know the magnitude of the current flowing through the circuit.
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
To measure small amounts of current in a circuit, it is utilized with the motor effect.
Since Galvanometer is a very sensitive instrument therefore it can't measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low resistance known as "shunt" resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt. In this way a Galvanometer is converted into Ammeter and can measure heavy currents without fully deflected.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
A galvanometer is a type of ammeter an instrument for detecting and measuring electric current. A galvanometer can be converted into ammeter by connecting resistance in parallel with it.