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The net effective resistance of 5 ohms, 10 ohms, and 20 ohms in series is 35 ohms.

The current through the net effective resistance is [ I = E/R ] = 120/35 = 3.429 Amp. (rounded)

Note: If you try this at home, be aware that these resistors will dissipate

the 5 ohm . . . 58.8 watts

the 10 ohm . . . 117.6 watts

the 20 ohm . . . 235 watts .

These are no ordinary resistors, such as hang on the wall in plastic bags at Radio Shack.

These would have to be 'power' resistors ... like heating coils in a toaster or hair-dryer.

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Q: At 120 vac what is the amp draw of total resistance series circuit with 5 ohms 10 ohms 20 ohms?
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Is there more resistance in the series circuit or the parallel circuit?

Ohm's Law says! R=V/I Resistance is directly proportional to Voltage. In series circuit, due to adding the resistance, total voltage will be increased, due to increasing of total voltage, total resistance of the series also be increased.


There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?

-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.


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What would the current draw be if there was six ten ohm resistors connected in series across a 120 volts?

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What will be the amps of a 12v 2amp circuit if there is a 12ohm resistor on it?

The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.

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