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How do you calculate the total mA needed to power 3 9v DC 200 mA devices?
Wiki User
∙ 13y ago
Separate devices should always be hooked up in parallel, and not series. Therefore, you would combine the total current requirement, which in this case is 600mA or 0.6A. You would therefore need a 9V power supply that is capable supplying at least 0.6A.
It depends on whether the devices are connected in series or parallel or some combination of the two.
The current in a series circuit is the same throughout the circuit. The current in a parallel circuit is the sum of the current in each parallel branch
If the three devices are connected in series, the required current is 200mA.
If the three devices are connected in parallel, the required current is 600mA
The total power required by a circuit is the sum of the power consumed by each component. It doesn't matter if the devices are connected in series or parallel. Power = voltage x current.
If the three devices are in series, the power consumed by one of them is 9 x .2 = 1.8 watts. The total power consumed is 1.8 x 3 = 5.4W
If the three devices are connected in parallel, the power consumed is 9 x .6 = 5.4W
Notice that the power consumed is the same for the series and parallel combination. The battery (or power supply) must be able to supply 5.4 watts.
Wiki User
∙ 13y ago
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