From the bottom of the motor contactor's heater block you connect the motor's leads to T1, T2 and T3. If the motor rotates in the wrong direction reverse any two leads on the bottom of the motor's contactor heater block.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
50:1
That is a 1956, 30HP Johnson motor.
Johnson made an RDE in 1956 that was a 30hp. I have one with and one without guess which one I use more.
A 1986 year model 30hp Johnson outboard uses a 50:1 fuel to oil ratio.
15L an hour?
No, you must use 2 cycle oil for the mix with gasoline.
One horsepower electric is 746 watts, so 30 horsepower is 22.4 KW. You don't specify the power factor or motor efficiency, so I am going to assume a power factor of 0.92 and an efficiency of 0.97, fair values for a 30 horsepower motor. Divide 22.4 KW by 0.92 and then by 0.97 and you get 25.1 KVA. Divide that by three and you get 8.4 KVA per winding. You don't say if the motor is delta or wye connected, so I'm going to assume delta, and multiply by the square root of 3 (1.732) to get 14.5 KVA per phase.
The dry weight of a 30hp Johnson outboard, 1985 model is 123 lbs.
Depends if it fiberglass or Aluminium. For Fiberglass you would be looking at around 50hp-60hp and and Aluminium would be between 30hp and 40hp.
Older models often have 1:50 ratio. Never have 1:100 This information should be on a sticker on the block or under the "hood"
fuel oil mixture 40:1 a good rule is to mix all outboards no matter what horse power a pint to 5 gallons