Dissolve 40 grams of solid NaOH into enough water that it dissolves completely. Transfer this to a volumetric flask. Then add water until the volume of the solution is 1 liter. Care is needed as heat is generated which affects the volume. It is best to make up with water to about 2 cm short of the mark, allow to cool and then add the balance of the water.
DANGEROUS: add 40g of NaOH to measured cylinder and then add just enough of water to fill up to 1 Liter
Added:
This is, in practice, the most DANGEROUS way to do. (Heat at dissolving NaOH may 'boil up' the added water). Theoretically however it is correct.
Best way:
First put about 900 mL water in a glass beaker, add 40 g NaOH to it while stirring the liquid.
Then after complete dissolution you eventually poor it into a volumetric glass 1000 mL cylinder or 1000 mL flask and fill it up to the 1 L mark.
However this will never give an analytically precise 1.000 M NaOH solution because of the hydrating and carbonating properties of NaOH in open air.
So it isn't necessary to follow these very precise procedures and measurements: you may skip the volumetric cylinder or -flask. Instead you can fill it up in the glass beaker to 1 L, if it has an 1.0 L.-mark, or even put it on a weighting device to fill up to 1.0 kg .
Add .4 grams solid NaOH to 1 liter of water. Molarity is moles per liter. Since the molar mass of NaOH is 40g/mol, a 1 M solution of NaOH would be 40 g (1 mole of NaOH) in 1 liter. One thousandth of this is .4 grams, giving 1 mM.
using the formula
mole=mass/molar mass,u can have the mass of NaOH that is to be dissolve in 1000dm^3 solution.
mole=1mol
molar mass=23+16+1=40g/mol
therfore, mass=mole *molar mass
mass=1mol*40=40g
dissolve 40g of NaOH pallets in 1000dm^3
1 molar solution means 1 mol of a substance (solute) per litre of solution.
1 mol = Molecular weight of the Substance
Molecular Weight of NaOH = 23 (Na) + 16 (O) + 1 (H)
= 40 gm
Hence,
1 mol NaOH = 40 gm NaOH
1 molar NaOH Solution = 40 grams NaOH dissolved in 1 litre water
0.01 molar NaOH Solution = 0.4 grams NaOH dissolved in 1 litre water
0.01M NaOH is 0.01 moles of NaOH in 1L of water. The molecular weight of NaOH is 23 + 1 + 16 = 40g/mole, and 0.01 moles would have a mass of 0.40g (0.01moles x 40g/mole).
So, adding 0.40g NaOH to 1L water gives a solution of 0.01M NaOH.
in one liter measure out 272 grams of NaOH pellets.
i make 0.2 M NaOH and i weight out 27.22grams of NaOH pellets in liter of water. I hope the conversion is just a tenth.
1mol of NaOH = 40gr of NaOH
M=mol/l
1M = 1mol of NaOH/1l of H2O
1M of NaOH = 40gr of NaOH/1l of H2O
dissolve 40gms NaOH in one lit of water
no-AH
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
no-AH
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
"Dilute NaOH" without any other specifications in a chemistry lab generally refers to a 6M solution of NaOH in water.
You need 2,4 g NaOH (0,06 moles).
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
dissolve 100g in 300ml water
4 moles or 160 g NaOH is required for one litre solution.
Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
MaVa=MbVb (6.0M NaOH)(x)=(0.10M solution)(1.0L) x=0.017L of 6.0M NaOH Convert to mL (1000mL in 1L) 17mL of 6.0M NaOH