Well you can't. Bismuth nitrate hydrolyses to form the insoluble oxynitrate and/or bismuth hydroxide depending on the conditions. It is soluble in nitric acid and hydrolyses at around pH0
how to prepare 1000 ppm solution of nickel carbonate
In order to prepare 500 ppm of lead solution from lead nitrate dissolve 0.799 gm of lead nitrate in 1000ml of water--add 1 or 2 drops of nitric acid.
Dissolve 101.1 g of potassium nitrate in 1 litre of water
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
I think this is inappropriate for asking on the Internet.
Solution A: Bismuth nitrate (0.17g) in AcOH (2mL) and H2O (8mL) Solution B: KI (4g) in AcOH (10mL) and H2O (20mL) Mix Solns. A and B and dilute to 100mL with H2O.
how to prepare 1000 ppm solution of nickel carbonate
In order to prepare 500 ppm of lead solution from lead nitrate dissolve 0.799 gm of lead nitrate in 1000ml of water--add 1 or 2 drops of nitric acid.
Dissolve 101.1 g of potassium nitrate in 1 litre of water
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
Dissolve 16,99 g silver nitrate in 1 L demineralized water.
I think this is inappropriate for asking on the Internet.
by adding 0.175 g of AgNO3 in 1000ml distlled water
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
Mix 90ml. sulfuric acid with 10ml. water, to this add 0.5gm. diphenylamine
Add potassium nitrate to distilled water while stirring continuously; stop adding potassium nitrate once the chemical becomes saturated and stops dissolving in the water. Filter the solution into an evaporating dish and measure the temperature of the solution. Measure the temperature and carefully heat the solution under low heat. Weigh the potassium nitrate to determine its solubility. You should find that approximately 36 g of potassium nitrate can be dissolved in 100 ml of water at room temperature (25 degrees Celsius). santosh kumar.batchu santoshkumar@gmail.com
0.5 = moles calcium nitrate / 3 L 0.1667 moles Ca(NO3)2 0.1667 * 148 = 24.7g Ca(NO3)2