Mechanical work is defined as force times distance, F X D = W
In a system with a gas the pressure of the gas exerts some force per unit area. If the gas changes in volume then that force has acted over some distance. For small changes in volume dW = P * dV where dV is some infinitesimally small change in volume and dW is the infinitesimall small amount of work done on or by the system. To calculate work you can then integrate P*dV from the starting volume to the ending volume. Note that if P is a function of V, such as the ideal gas case where P = NRT/V then the integral becomes more complex, W = Integral(NRT/V * dV). This works out to W = NRT * ln(V2/V1) assuming positive work is work done on the system. In the case of gas expanding against atmospheric pressure P is constant so W = P * (V2-V1) again assuming positive work is work done on the system. If gas expands against a vacuum then the P being pushed against is zero so no work is done.
You can show that the units work out by analyzing the units involved:
P = Force / Area = Force / Distance ^2
V = Distance ^3
P*dV = Force / Distance ^2 * Distance ^3 = Force * Distance = Work
W=pav
Heat of the gas is lost as work done by the gas.
zero. because in free expansion volume of gas increase against any resistance.
They have the same units- Joules - so can be equated. Work is something actually done, and in doing work energy is expended, but you can also talk of doing work to store energy. For example in running a compressor to fill a cylinder with compressed gas, energy is supplied to the compressor motor, work is done by the compressor, and the result is stored energy in the gas. Fuels such as coal have potential or stored energy, which can be released to do work. So I think the fundamental is energy, but when energy is used, work results. Hope that makes sense!
No, HEAT is work done!
work done on the system: when a surrounding does work on the system the total energy increases so work done is positive..........
work done is zero when gas expands in vacuum.sarin madhusoodanan
Heat of the gas is lost as work done by the gas.
Yes. The work is being done by whoever is pushing rather then the engine, but work is being done. Any time a force is applied through a distance, work is being done.
In mechanics,work done(work=force.displacement of body) by a body is independent of path.It only depends on the initial and final state of the body.However in thermodynamics,the work done by an ideal gas(work=pressure.change in volume of gas) depends on the path taken(isochoric,isothermal,isobaric,adiabatic)
General repairs.
Heating that results from work done on the system, such as when a gas is compressed within a piston.
Work Done = Fs cos 0 OR- Work done by an expanding gas against a constant pressure would be w=F*d (Recall that F=PA; from P=F/A) W= (PA)d (volume = area*d) Therefore Work done = p (change in volume)
This work was done by prisoners bullied into helping the SS in this way.
dude im not gonna do your homework for you.
zero. because in free expansion volume of gas increase against any resistance.
Work Done = Force x Displacement, so if the displacement is zero, the work done will be zero. There will be no work done.
They have the same units- Joules - so can be equated. Work is something actually done, and in doing work energy is expended, but you can also talk of doing work to store energy. For example in running a compressor to fill a cylinder with compressed gas, energy is supplied to the compressor motor, work is done by the compressor, and the result is stored energy in the gas. Fuels such as coal have potential or stored energy, which can be released to do work. So I think the fundamental is energy, but when energy is used, work results. Hope that makes sense!