0
#include<stdio.h>
#include<conio.h>
main()
{
int a=0,b=1,c,i,n;
clrscr();
printf("enter the limit of series\n");
scanf("%d",&n);
if(n==0)
printf("%d\n",a);
else
printf("%d\n%d\n",a,b);
for(i=2;i<=n;i++)
{
c=a+b;
printf("%d\n",c);
a=b;
b=c;
}
getch();
}
Wiki User
∙ 11y ago
Wiki User
∙ 12y ago#include
void main()
{
int i,f1=0,f2=1,f,n,sum=0;
printf("enter the range dou you want");
scanf("%d",&n); //it identifieses the range number do you want
printf("d",f1,f2);// first two fibanacci numbers
for(i=1;f<=n;i++) //to generate Fibonacci numbers
{
f1=f2;
f2=f;
f=f1+f2;
s=s+f;
printf("%d",f);
} //end for loop
printf("%d",sum);
}end of main
Wiki User
∙ 9y ago#include<iostream>
using namespace std; int main()
{
cout << "Fibonacci sequence up to 100...
int f1 = 0;
int f2 = 1;
cout << f1 << endl;
while (f2<100)
{
cout << f2 << endl;
int next = f1 + f2;
f1 = f2;
f2 = next;
}
}
Wiki User
∙ 10y ago#include<iostream>
int main()
{
int x=0, y=1, sum=x+y;
std::cout<<x<<" ";
std::cout<<y<<" ";
while( y<1000000 )
{
std::cout<<(y+=x)<<" ";
x=y-x;
sum+=y;
}
std::cout<<std::endl;
std::cout<<"Sum = "<<sum<<std::endl;
return(0);
}
Wiki User
∙ 10y ago#include<iostream>
int main()
{
int x=0, y=1;
std::cout<<x<<" ";
std::cout<<y<<" ";
for( ;y<1000000; )
{
std::cout<<(y+=x)<<" ";
x=y-x;
}
std::cout<<std::endl;
return(0);
}
Wiki User
∙ 10y ago#include<iostream>
int main()
{
int x=0, y=1;
std::cout<<x<<" ";
std::cout<<y<<" ";
for( ;y<1000000; )
{
std::cout<<(y+=x)<<" ";
x=y-x;
}
std::cout<<std::endl;
return(0);
}
Wiki User
∙ 13y agoThis question has been asked many times and answered many times please refer to previous answers. Also any future questions you may have have probably been asked and answered by previous students doing the same course as you.
Actually doing the work your self rather than looking for the easy way will benefit you the most because you will learn something. Using someone else work is deceitful and will only cause you to be a failure as a person and in your academic endeavors.
Wiki User
∙ 10y ago#include<iostream>
int main()
{
int x=0, y=1;
std::cout<<x<<" ";
std::cout<<y<<" ";
while( y<1000000 )
{
std::cout<<(y+=x)<<" ";
x=y-x;
}
std::cout<<std::endl;
return(0);
}
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Would you Write c plus plus program using array for Fibonacci number?
You can write a C++ fib pro using arrays but the problem is the prog becomes very complicated since u need to pass the next adding value in an array.....
Which program produces the obj file assembly or C plus plus?
A compiler produces object code, which is an obj file.
Flowchart for Fibonacci series in c language?
#include<stdio.h> void printFibonacci(int); int main(){ int k,n; long int i=0,j=1,f; printf("Enter the range of the Fibonacci series: "); scanf("%d",&n); printf("Fibonacci Series: "); printf("%d %d ",0,1); printFibonacci(n); return 0; } void printFibonacci(int n){ static long int first=0,second=1,sum; if(n>0){ sum = first + second; first = second; second = sum; printf("%ld ",sum); printFibonacci(n-1); } }
Fibonacci c plus plus program?
#include<iostream> int main() { int x=0, y=1; std::cout<<x<<" "; std::cout<<y<<" "; while( y<1000000 ) { std::cout<<(y+=x)<<" "; x=y-x; } std::cout<<std::endl; return(0); }
Is there an answer book for the A plus program?
The A Plus Program is an initiative, not a test. So no, there is no answer book.
Program to generate Fibonacci series using storage class in c plus plus?
i dn't know. haha
Create a c plus plus program to generate Fibonacci series?
#include #include void main() { clrscr() int a=0,b=1,c,i,n; coutn cout
Can you have the program in C plus plus for recursive function generating a series of terms?
Yes, this can be done. For example for Fibonacci series. You will find plenty of examples if you google for the types of series you need to be generated.
What is the name of the series 1 plus 1 plus 2 plus 3 plus 5 plus 8 plus 13 plus 21 plus 34 plus .................................?
That's the beginning of the Fibonacci series.
What is the name of the series 1 plus 1 plus 2 plus 3 plus 5 plus 8 plus 13 plus 21 plus 34 plus .........?
It's Fibonacci's
A c plus plus program to find Fibonacci series?
#include<iostream> int main() { int x=0, y=1; std::cout<<x<<" "; std::cout<<y<<" "; while( y<1000000 ) { std::cout<<(y+=x)<<" "; x=y-x; } std::cout<<std::endl; return(0); }
How do you write a c plus plus recursion program to find fibonacci series?
#include<iostream> unsigned fib (unsigned term, unsigned a=0, unsigned b=1) { if (term<1) return a; return fib (--term, a+b, a); } int main() { std::cout << "Fibonacci (1000th term): " << fib (1000) << std::endl; }
What are the roots X2 plus x-1 equals 0?
The roots are -1/2 of [ 1 plus or minus sqrt(5) ] . When rounded: 0.61803 and -1.61803. Their absolute values are the limits of the Fibonacci series, or the so-called 'Golden Ratio'.
Would you Write c plus plus program using array for Fibonacci number?
You can write a C++ fib pro using arrays but the problem is the prog becomes very complicated since u need to pass the next adding value in an array.....
Write a c plus plus program to find the sum of series S equals 1 plus x2 plus x3 plus x3. plus xn?
(xn+2-1)/(x2-1)
How do you write C plus plus program to generate sum of the series up to n number?
pseudocode: int itotal = 0; int inum = 0; //* Use console routine to prompt and get the value of inum which would be //* the number to which the sum needs to be evaluated for (int i = 1; i < inum + 1; i++) { itotal = itotal + i; } //* Use console routine to display the value of itotal
Which program produces the obj file assembly or C plus plus?
A compiler produces object code, which is an obj file.
