two nand gates
9,to implement a half adder 5 nand gates and for a full adder,another xor gate is required consisting of 4 nand gates. thus a total of 9 nand gates are required for a full adder.
As such an OR gate should do the job...but if the question is of using gates other than the simple OR, it should be a combo of NOR and NOT gates; where-in, the NOT gate comes after the NOR gate. Factfully speaking: The output of a NOR gate when fed to a NOT gate shall give you an OR gate. cheers :) Anish Murthy Airpula, RF Design Engineer (F.A.E) Ceramic & Microwave Products Group, Dover Corporation Inc, United States of America
A&B = ((A&B)')' So two, it would go a - | ==NAND--=NAND-- b - | By using two NAND gates back-to-back, you can create a normal AND gate.
A 2 input NAND gate requires 4 NOR gates.A 3 input NAND gate requires 5 NOR gates.A 4 input NAND gate requires 6 NOR gates.etc.
Check this link http://www.dumpt.com/img/viewer.php?file=bd6b3mqsa66fhr6c76l1.bmp
an AND gate and a NOT gate
universal gates are the ones from which we can design other gates also. for eg. NAND and NOR gates. they help in forming the uniformity in the circuits.
when the two inputs are shorted, a NAND gate acts like a NOT gate. hence AND = NAND + NOT For OR gate, inverse both the inputs before connecting them to a NAND gate. So three NAND gates would be needed.
Any logic gate from which all other logic gate functions can be derived. The two universal gates are NAND and NOR.
pass the inputs through an nand gate and again pass them through inverter,which is again formed by an nand gate
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universal logic gate is a gate using which you can make all the logic gates there are two such gates NOR gate and NAND gate