It depends on how deep you fill the pool. So, let's take the most common depths for a 33-foot round pool; 3, 4 and 5 feet:
if the pool is a 27 ft circle and it is filled to 4 ft V= ¶r2h 2289.789 cubic feet=3.141*182.25*4 and 1 gallon=.133680 ft³ so 2289.789 *.133680=17128.811 gallons
To calculate this the depth would also be needed
29,555.46 gallons.
Apx 18420 gal. in a 28 round 4ft pool
7,559.9811 gal.
A round pool that is 16 feet across and is filled with 48 inches of water will contain about 6,041 gallons of water.
6015.77 gallons
5300 Gal
15000 gallons
18,000
Just a little over 6,000 gallons.
13,346 gallons per vertical foot.
There are 6016.20 gallons of water for every 1 foot of heigth. Therefore, the total gallons is 24,065gallons. Hope this helps. Louis Daigle
18,506 U.S. gallons
How large is the pool? In ground or above ground? Shape? Above ground is easier to calculate. I have an oval above ground pool which is 18 x 38. It holds approx. 15,000 gallons. To get an accurate answer, you need to be far more specific.
We have a 24' foot round above ground with 13000.00 gallons of water and that only requires a 1 hp pump a 2 hp pump may be overkill and cost more to operate
10053.82 gallons (US) 8371.568 gallons (UK)