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How many grams of Ca-OH-2 are needed to prepare 100 mL of solution of 0.1 M Ca-OH-2?
Wiki User
∙ 9y ago
M = moles/liter
100 ml = 0.1 liter
so 0.01 mole NaOH / 0.1 liter = .1 M NaOH
you can find how many grams of NaOH in .01 moles by multiplying .01 by the atomic weight of a mole of NaOH, which you can find by adding up the atomic weight of Na, and O, and H.
Wiki User
∙ 14y ago
Wiki User
∙ 9y ago0.1 M Ca(OH)2 = 0.1 mol/L = 0.01 mol/100mL = 0.01(mol/100mL) * 74.093(g/mol) = 0.74 g/100mL Ca(OH)2
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How many grams of CaOH2 are needed to prepare 300.0 mL of a 0.115 M solution?
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
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How many grams of CaOH2 are needed to prepare 300.0 mL of a 0.115 M solution?
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
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