0
16384
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What is instruction format in computer architecture?
The connection between the hardware and software components of a computer creates the computer architecture. It is basically how the components are connected to form a complete system. Sir Frederick P. Brooks and Sir Lyle R. Johnson presented the idea of computer architecture in 1959. A set of operating codes, operands, an opcode, and an addressing mode make an instruction. The instruction format is the standard instruction format that is directly used by the CPU. The instruction format is just the sequence of bits (0,1). The group of these bits is called a field. Each field of the system provides specific information for a particular task to the CPU about the instruction's operation and the instruction's data. The most fundamental difficulty in format design is instruction length. The longer the command will, take longer the time to fetch it. The types of Fields are discussed below: Operation Field: It specifies the operations that are performed by the instructions like, ADD, SUB, etc. It can be any value or number on which the task has been performed. Operation field is mandatory for every instructor Address Field: It specifies the address of the operand. It refers to the address where the operand is stored. On the basis of multiple address fields, the instruction is categorised as follows: Zero address instruction: The operand positions are implicitly represented in zero address instructions. The stack-organized computer system supports these commands. One address instruction: This instruction manipulates data with the help of an implicit accumulator. Accumulator is a register that performs a logical process for the CPU. It uses one address field. Two address instructions: This address instruction is mostly used. This address command format has three operand fields. In the two address sections, registers or memory addresses can be used. Three address instructions: A three-address command must contain three operand components in its format. These three fields could be registers or memory locations. The instruction pipeline in computer architecture The instruction pipeline in computer architecture shows the system's instruction flow. It has 4 major segments, which are discussed below. Segment 1: The instruction fetch part can be performed using first in, first out (FIFO) buffers. Segment 2: The second section decodes the memory-fetched command before the effective location is computed in a different arithmetic circuit. Segment 3: The input is fetched from memory. Segment 4: The execution of the instructions is performed. Some of the features of instruction are : Addressing model: This is the first part of the instruction format. Data over the instruction format can be represented as an addressing format, and data is stored in the computer's memory or in the CPU's register OPCODE(operation code): This is the second part of the instruction format, and the opcode instructs the processor to perform the desired operation. Operand: Depending upon the processor instruction format, it contains zero to three operands, and this part specifies the data or points to the address of the data.
What is a series of 8 bits?
A series of 8 bits is a Byte.
What are pebble like bits of magma that harden before they hit the ground?
Pebble-sized bits of volcanic rock are called lapilli.
Do vector graphics have pixels?
No, they are shape based and do not have pixel bits.
What are fine bits of rock and soil deposited on the land by a river?
sediment
How many nuMBer of address lines required for 8 MB of memory?
It takes 23 address lines to address 8 mb of memory.
The number of memory locations that a CPU with 16 bit program counter can address is?
The number of memory locations that a CPU with 16 bit program counter can address is 65,536. However, the 8086/8088 has a segmented architecture giving a total addressibility of 20 bits or 1,048,576 locations. Without changing the code segment register, though, you can only access 65,536 locations.
How many bits of address bus are required to address 1mb memory?
You need 20 bits of address bus to address 1 Mb of memory.
How many address lines are needed to access 256KB of main memory?
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
How many lines of the address must be used to access 2048 bytes. How many of these lines are connected to the address input of all chips?
That depends on the memory architecture of the system.if the memory chips are byte wide and not used to create a multibyte bus, 11 address bits are needed.if the memory chips are 32 bits wide, 9 address bits are needed (with the CPU internally selecting which of the 4 bytes it will use).it the memory chips are 64 bits wide, 8 address bits are needed (with the CPU internally selecting which of the 8 bytes it will use.if the memory chips are 4 bits wide, 12 address bits will be needed and the CPU must perform 2 memory cycles per byte that it needs. (yes, I have seen a computer that worked this way!)etc.
When the low order bits of the address are used to select the memory bank it is?
When the low order bits of the address are used to select the memory bank it is interleaved.
How many memory locations are possible with 32 bits?
2^32
What is the memory's addressibility?
HI I am Ahtarva,The addressibility is how many bits does that particular processor or micro-controller's architecture use to specify the address of a memory location in the memory. For example if someone say that addressibility is 8 bit then your memory address contains 8 bits and at maximum you have 2^8 different memory locations (or say memory addresses in your device). Here 2^8 is called Address space.
How many locations of memory can you address with 16-bit address?
each line can address two bits, so 2^14 = 16384 locations
What is memory address register of Intel 8085?
8 bits
How many minimum number of bits that are needed to address 2000 locations?
11 bits. 211 = 2048
What is equal to one trillion memory locations?
That would be a terabit. The unit "terabyte" is more commonly used, but each byte is actually 8 memory locations (bits).
