The current is determined by the load. So if the conductors are designed to carry the resulting load current, then the high-voltage supply will have no effect. If not, then the conductors will overheat, their insulation will fail, and a short-circuit will result. However, the conductor's insulation must also be capable of withstanding the high voltage; if not, then the insulation will break down and a short circuit will result.
Ohm's Law states that Voltage = Resistance (Ohms) * Current (Ampere). So when you increase voltage, you increase current.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
Generally, yes. It would depend on the device you are talking about. In a resistor a change in current will result in an instant change in voltage. Inductors and capacitors do not change instantaneously but will over time.
The resistance remains constant. The voltage would change, in accordance with Ohms' law, with a change in current.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
Yes. If voltage leads the current, the impedance is inductive (this would be the case if the load is a motor). If current leads the voltage, the impedance is capacitive (this would be the case for a CFL light bulb).
1) voltage level up-down2) voltage level down-up3) isolationAnswerBecause transmission would be impossible except at high voltages/low load currents due to enormous voltage drops that would otherwise occur, and these are achieved using transformers..
low current high voltage power dissipation in power line = I2R the resistance of the power line is hard to reduce, especially when it is a long transmission line. but reducing the current through the line reduces losses as the square, a dramatic savings. reducing voltage would have no effect and would dramatically increase losses due to increase in current to try to deliver same power.
To do it properly would require rewinding the motor with thicker wires in order to deal with the higher current caused by the higher voltage.
The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.The series resistance is 4 x 50 = 200 Ohms. You would need additional information to get the current; usually this is calculated from the voltage. current = voltage / resistance.
how would you show the heating effect of a current?
current would go to a maximum, (if there was voltage present), if there was no voltage, no current would flow. the only thing that would limit the current flow (if voltage is present) is the small resistance of the cables, but say there was no resistance it would be like in a short circuit maximum current would flow at the instant voltage is applied. that is why RCD's work as they should, you want the most amount of current to flow at once because otherwise if the current was limited it would not trip in time to stop someone getting electrocuted.