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The balanced reaction is this:

(NH4)CO3 + Ag2SO4 ---> Ag2CO3 + (NH4)2SO4

To solve this:

1) convert the 10.0 grams of (NH4)CO3 into moles (see Related Questions)

2) determine the stoichiometry of the reaction to determine how many moles of Ag2CO3 are produced (see Related Questions)

3) because there is an excess of Ag2SO4 , the number of moles of (NH4)CO3 will determine the number of moles of Ag2CO3

4) convert the number of moles of Ag2CO3 into grams (see Related Questions)

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Q: If 10.0g of ammonium carbonate are combined with an excess of silver sulfate to produce silver carbonate and ammonium sulfate how many grams of silver carbonate are produced?
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