Put 5 sheep in each of three small pens... THEN - build a larger pen enclosing the three smaller ones. The smaller pens each have an odd number of sheep in them (5 in each) - and the large pen has a total of 15 sheep enclosed within it !
You don't need to use all 35 pigs. You only need to ensure that there is an uneven number of pigs in each of the four pens. You could, for example, put 1 pig in each pen and therfore solve the problem.
1st pen- 3 pig
2nd pen- 3 pigs
3rd pen- 3 pigs
4th pen- It is around the 1st,2nd and 3rd pen.
This is correct
At least one pen is fully contained within another.
No. 21 pigs in each of the 4 pens is 21 times 4 which equals 84 pigs. 84 is an even number.
snotpossible
Unless you mean at least 20 chickens and/or *within* 7 days, it is impossible, as an odd number of odd numbers will always have an odd number as their sum.
two birds had 7 and one had 5
Odd, they only have one toe on each leg. Altogether it would be even, I guess.
Humans have 46 chromosomes. To be more specific, they have 22 somatic (body) chromosomes from each parent, and one sex chromosome from each parent. Added together, humans have 46 chromosomes (or 23 pairs). However different animals have different numbers of chromosmes. But under normal circumstances, each has 1 copy from each parent, and 1 copy of a sex chromosome from each parent. For instance, mice have 40 chromosomes, a horse has 64, a cat and dog both have 38, and some species of elephants have 56. It depends on the animal because each animal has a different number of chromosomes.
Odd Bull died on 1991-09-08.
3.75
Even, they have four toes on each hoof.
No. The sum of four odd numbers will always be an even number!
Uneven does not necessarily mean odd. It can also mean unequal. So, buckets with 3, 4, 5, 6, 7, 8, 9 pigs can be said to have an uneven number in each.
it's impossible i thinkActually, if you consider the unrealistic situation of concentric pens with 1 sheep in the inner-most pen, 4 in the next outer pen, 18 in the next outer pen and finally 4 in the next outer pen, there are an odd number in each pen (1, 5, 23 and 27 sheep in each respective pen) and a total of 27 sheep overall.
LCM stands for "least common multiple." By definition, they are multiples of each number, odd or even.
If you have six boxes, with an odd number of coins in each box, in total you would have an EVEN number of coins. Therefore, this isn't possible. (odd + odd = even, odd + odd + odd = odd, etc. - if you add an even set of odd numbers, the total will always be even.)
Sure, if each of the dimensions (length, width, and height) is an odd number of units.
Five.
An odd number plus an odd number will be an even number. Odd number A is (even number + 1) Odd number B is (even number + 1) A + B = (even number + 1) + (even number + 1) = even number + even number + 2 Since all even numbers are divisible by 2 and 2 is divisible by 2, each part of the result is divisible by 2, so the sum as a whole is divisible by 2, which means it is an even number.
27 is an odd number.
An odd number minus an odd number is an even number.