On object falling under the force of gravity (9.8 m/s2) would, in a vacuum, fall a distance of 706 metres in 12 seconds. In a non-vacuum, i.e. air, the object would fall less distance in the same time due to drag.
xt = 0.5 (9.8) t2
29.4
Ignoring air resistance, the mass, weight, color, acceleration and direction of such a body are constant, whereas its speed is not. Note: "A height" is the only place from which an object can fall.
29.4 m/s
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
An object dropped from rest will have a downward velocity of (9 g) = 88.2 meters per second after 9 seconds. Ignoring air resistance, the mass of the object is irrelevant. All masses fall with the same acceleration, and have the same downward velocity after any given period of time.
Ignoring air resistance, it would be 706 meters .
29.4
At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
Ignoring air resistance, the mass, weight, color, acceleration and direction of such a body are constant, whereas its speed is not. Note: "A height" is the only place from which an object can fall.
194fps
29.4 m/s
The answer depends on the degree of sophistication. For an elastic object, ignoring any air resistance, the bounce height, h = drop height, d. If the object is elastic, with coefficient of restitution = r, then h = r2*d. The equation becomes more complex as other effects such as air resistance are introduced into the calculation.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
After 3.5 seconds of free-fall on or near the surface of the Earth, (ignoring effectsof air resistance), the vertical speed of an object starting from rest isg T = 3.5 g = 3.5 x 9.8 = 34.3 meters per second.With no initial horizontal component, the direction of such an object's velocitywhen it hits the ground is straight down.
If you're talking about an object falling straight downward, that object being affected by a gravitational pull of 9.81m/sec, ignoring air resistance, it would take the object around 5 seconds to reach 49m/sec.
An object dropped from rest will have a downward velocity of (9 g) = 88.2 meters per second after 9 seconds. Ignoring air resistance, the mass of the object is irrelevant. All masses fall with the same acceleration, and have the same downward velocity after any given period of time.