Ignoring air resistance, I get this formula:
Maximum height of a vertically-launched object = 1.5 square of initial speed/G
I could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
In a car the maximum acceleration (deceleration) caused by breaks is about 1 g. Thus the faster the initial speed, then the greater the time AND distance needed to come to a stop will be required.
initial velocity of the kick = 28.06 m/s
0.82 metres.
Maximum velocity is the fastest an intem can go, while optimum velocity is the "best" speed it can travel on. For a car optimum velocity could mean either where you get the best MPG, or where you can go round corners/over bumps without the car starting swaying, or something like that.
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
In a car the maximum acceleration (deceleration) caused by breaks is about 1 g. Thus the faster the initial speed, then the greater the time AND distance needed to come to a stop will be required.
initial velocity of the kick = 28.06 m/s
f = (mv^2)/r therefore the longer the length (ie. r) then the smaller the velocity, if the force is assumed to be constant.
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
0.82 metres.
0.82 metres.
18
Maximum velocity is the fastest an intem can go, while optimum velocity is the "best" speed it can travel on. For a car optimum velocity could mean either where you get the best MPG, or where you can go round corners/over bumps without the car starting swaying, or something like that.
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
When a pendulum reaches its maximum elongation the velocity is zero and the acceleration is maximum
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.