the power will also increase as it is proved in my experiment
It doesn't. Assuming the load stays constant when you reduce voltage you reduce current. Power is derived by multiplying current x voltage. If they are both going down power must decrease.
At what voltage? When you know the voltage then, to get the amps those kilovolt-amps contain, you simply divide the kilovolt-amps by the voltage.
Watts = Amps x Volts. Amps = Watts/Voltage. Amps = 2500/apply voltage here.
If the voltage in your vacuum is 120 then you divide the Wattage by the Voltage to get 3 amps.
watts = amps (times) voltage watts (divided by) voltage = amps 140 (div by) 120 = 1.66 140 (div by) 125 = 1.12
A low voltage fuse should be rated for 30 amps.
There are 746 watts in 1 HP. Watts = amps x volts. It depends on the voltage rating of the motor. Amps = 746/volts = ? need voltage.
At what voltage? If you know the voltage then, to get the amps those kilovolt-amps contain, you simply divide the kilovolt-amps by the voltage.
At what voltage? When you know the voltage then, to get the amps those kilovolt-amps contain, you simply divide the kilovolt-amps by the voltage.
For a fixed resistance (ohms) current increases as voltage increases. Since Watts equals Volts x Amps x Power Factor then Watts would increase as voltage increases. The resistance would usually be fixed, but if you had a variable load resistance as the resistance decreased and the voltage remained constant, the current would increase and watts would therefore increase. Watts = Volts x Amps x Power Factor Volts = Amps x Ohms Power Factor is 1 for a resistive load.
Voltage remains constant; current increases.
After breakdown voltage is reached in a zener diode the current increases drastically.
If you don't change the voltage between the ends of the circuit,then higher resistance in the circuit means lower current (amps).
nothing
By Decreasing the excitation voltage the terminal voltage will decrease and similarly by increasing the excitation voltages the terminal voltage will also increases.
Watts = Amps x Volts. Amps = Watts/Voltage. Amps = 2500/apply voltage here.
If resistance increases and voltage stays the same, then current decreases. Ohm's Law: Current equals Voltage divided by Resistance.
P=VI If current (I) increases then P will increase proportionally. That is, assuming that voltage (V) remains constant. If voltage decreases and current increases or vice versa, proportionally then P will remain the same.