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The substances produced when KOH aq neutralizes HCl aq are?
Auburntiger52
KOH (aq) + HCl (aq) = KCl (aq) + H20 so potassium chloride and water - KCl solution
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∙ 13y ago
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What is the molarity of a KOH solution if 24.6 mL neutralizes 44.0 mL of a 0.211 M HCl?
0.377
What mass of h2o is produced when 0.400 moles of koh react completely in the following equation koh plus hcl equals kcl plus h2o?
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
What is the chemical reaction between hcl plus koh?
KOH + HCl ---> KCl + H2O
What are the products of the neutralization reaction of KOH with HCl?
Potassium chloride and water result from this reaction: KOH + HCl = KCl + H2O
Does an alkali easily neutralize a concentrated acid or a dilute acid?
Alkalies can neutralize both concentrated and dilute acids, but dilute acids are 'more easily' neutralized (i.e. require a smaller amount of alkali for the same amount of acid). It is a simple chemical reaction, the amount of alkali required to neutralize an acid can be calculated if you know how they react and the strengths of the acid and alkali. E.g. if you use Potassium Hydroxide (KOH) to neutralize Hydrochloric acid (HCL) the reaction is: KOH + HCL --) KCL + H2O So one molecule of KOH neutralizes one molecule of HCL If you have 1 molar KOH, then : 10 ml of dilute HCL (0.1 molar strength) will be neutralized by 1 ml of KOH 10 ml of a strong HCL (10 molar strength) will be neutralized by 100 ml of KOH Hope that helps.
What is the molarity of a KOH solution if 24.6 mL neutralizes 44.0 mL of a 0.211 M HCl?
0.377
What mass of h2o is produced when 0.400 moles of koh react completely in the following equation koh plus hcl equals kcl plus h2o?
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
What is the chemical reaction between hcl plus koh?
KOH + HCl ---> KCl + H2O
Does an alkali easily neutralize a concentrated acid or a dilute acid?
Alkalies can neutralize both concentrated and dilute acids, but dilute acids are 'more easily' neutralized (i.e. require a smaller amount of alkali for the same amount of acid). It is a simple chemical reaction, the amount of alkali required to neutralize an acid can be calculated if you know how they react and the strengths of the acid and alkali. E.g. if you use Potassium Hydroxide (KOH) to neutralize Hydrochloric acid (HCL) the reaction is: KOH + HCL --) KCL + H2O So one molecule of KOH neutralizes one molecule of HCL If you have 1 molar KOH, then : 10 ml of dilute HCL (0.1 molar strength) will be neutralized by 1 ml of KOH 10 ml of a strong HCL (10 molar strength) will be neutralized by 100 ml of KOH Hope that helps.
What are the products of the neutralization reaction of KOH with HCl?
Potassium chloride and water result from this reaction: KOH + HCl = KCl + H2O
How many milliliters of 0.45M HCl will neutrilize 25.0mL of 1.00M KOH?
You have : --------------------------------------… V sub 0.45M HCl = ( V sub 1.00M KOH ) ( M sub KOH / M sub HCl ) V sub 0.45 HCl = ( 25.0 ) ( 1.00 / 0.45 ) = 55.56 mL <-----------------------
How do you make potassium chloride with H20?
When KOH reacts with HCl, these products are formed. This is a neutralization reaction. KOH is a base while HCl is an acid.
What kind of reaction is the addition of KOH to HCl?
KOH + HCl -> KCl + H2O This is a neutralization reaction. You know because it produces water and a salt.
What salt would form from HCl and KOH?
KCl
What is left when a base is neutralize?
Water and a salt (a salt referring to any ionic compound). An example would be HCl neutralizing KOH. HCl+KOH-->H2O+KCl
What makes KCl a salt and why?
A salt is the product of the reaction between a base and an acid; potassium chloride may be obtained from HCl and KOH: HCl + KOH = KCl + H2O
What acid reacts with KOH to produce to salt KCI?
Hydrochloric acid will... HCl + KOH = KCl + H2O
