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Regard the candles as being of unit height then the first candle's height after time 't' is 1 - t/6 and the second candle's height is 1 - t/8.

When the first candle is half the height of the second candle then :

2(1 - t/6) = 1 - t/8 : 2 - t/3 = 1 - t/8 : 1 = t/3 - t/8 = 5t/24 :

t = 24/5 = 44/5 hours = 4 hours 48 minutes.

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Q: Two candels are of same height but different thickness are lighted the 1st burns off in 6hrs and the 2nd burns off in 8hrs find the time in which the 1st candle be half the height of the 2nd candle .?
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