If there are two digits than the first one is ten times its value.
So as an algebraic equation we get
10A + B - 3 = 7(A x B)
This can be simplified to
10A + B - 3 = 7A + 7B
and this reduces to
10A - 7A = 7B - B +3
or
3A =6B +3
A solution to this is
3(3) = 6(2) +3
Which would make the original equation
32 = 7(3+2)-3
27
26.
804
27
The sum is 22 times the sum of the three digits.
27
it is 10
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27
333222111
The first digit has to be in the set [1-6] because, if it were zero, it would not be a three digit number. The number of combinations, not using duplicates, of three numbers from the set [0-6] is 6 times 6 times 5, or 180.
2
There is no number. 100 is the only one that has a hundreds digit. It's impossible.