+1 to each H
+4 to each C
-2 to each O
C=x
O= -2 (rule)
(CO3)-2 has a charge of -2
x+ 3(-2)=-2
x=4
C=4
O=-2
This is a anion. c shows +5 oxidation number.
+4 is the oxidation number of carbon in bicarbonate HCO3-, the same as in CO2 and H2CO3
Hydrogen's oxidation number is +1. Oxygen's oxidation number is -2. Carbon's oxidation number is +4.
The charge of ion is -1. The oxidation numbers of hydrogen and oxygen are +1 and -2 respectively. By balancing the charges, carbon is in +4 state.
+1 for each H, +4 for C and -2 for each O
+1 for each H, +4 for C, -2 for each O.
+1 for each H, +4 for C and -2 for each O
4
This looks like it would be zinc(IV) carbonate, but that is not possible, since Zn has only one oxidation state, and that is 2+. So, the compound should be Zn(HCO3)2 as HCO3 (bicarbonate) has an oxidation number of 1-. So, Zn(HCO3)4 would not exist.
I believe K2CO3.
CoCl3 is the chemical formula.Common oxidation states of cobalt include +2 and +3, so possible chlorides are: CoCl2 and CoCl3 , but the last one is rare.(CoF3 (Co(III)-fluoride) is a better possibillity to prove this oxidation state)Maximum oxidation state is +5, though Cobalt can easily 'coordinate' with in total 6 coordinative groups (=CG) and negative ions: Co(CG)4Cl2 (a coordinative group migh be a < -N| >-atom group of ammonia, ethylenediamine or haemoglobin)
YES...CH4 + SO42- → HCO3- + HS- + H2O, is only one formula.
Carbon has an oxidation number of +4 in both carbonate and bicarbonate. Oxygen as usual has an oxidation number of -2, and hydrogen has an oxidation number of +1. Therefore, the ion CO3-2 has six negative charges from oxygen partly balanced by four positive changes from carbon for a net of -2, and HCO3-1 has six negative charges from oxygen partly balanced by one positive from hydrogen and needs for plus four from carbon for an overall value of -1.
This looks like it would be zinc(IV) carbonate, but that is not possible, since Zn has only one oxidation state, and that is 2+. So, the compound should be Zn(HCO3)2 as HCO3 (bicarbonate) has an oxidation number of 1-. So, Zn(HCO3)4 would not exist.
I believe K2CO3.
CoCl3 is the chemical formula.Common oxidation states of cobalt include +2 and +3, so possible chlorides are: CoCl2 and CoCl3 , but the last one is rare.(CoF3 (Co(III)-fluoride) is a better possibillity to prove this oxidation state)Maximum oxidation state is +5, though Cobalt can easily 'coordinate' with in total 6 coordinative groups (=CG) and negative ions: Co(CG)4Cl2 (a coordinative group migh be a < -N| >-atom group of ammonia, ethylenediamine or haemoglobin)
YES...CH4 + SO42- → HCO3- + HS- + H2O, is only one formula.
Carbon has an oxidation number of +4 in both carbonate and bicarbonate. Oxygen as usual has an oxidation number of -2, and hydrogen has an oxidation number of +1. Therefore, the ion CO3-2 has six negative charges from oxygen partly balanced by four positive changes from carbon for a net of -2, and HCO3-1 has six negative charges from oxygen partly balanced by one positive from hydrogen and needs for plus four from carbon for an overall value of -1.
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
Oxidation number of Si is +4.Oxidation number of O is -2.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.