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IR drop across a resistance is voltage.
The letter I means current, and the letter R means resistance. Current times resistance, by Ohm's law is voltage.
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What is IR drop?
IR Drop means voltage drop. As voltage drop across any resistance is product of current (I) passing through resistance and resistance value(R ) , it is often written as IR drop.
The voltage drop in each resistance is?
V=IR by ohms law. Voltage across the resistor is the product of current flowing and resistance of the conductor at constant temperature.
How would you find out the length of the wire effects the voltage drop across the wire when the current passing is kept constant?
A: There are tables that qualify IR drops for wire lenght. All wire do offer resistance to current this current will cause directly a volatge drop according to the wire resistance so it can be measured to find the IR drop
How are the voltage drop across R and XL related in series RL circuit?
Voltage drop across a circuit is IZ, where I is current and Z is impedance. In other words IZ = IR + jIX, where R is resistance and X is inductance
Why is there a voltage drop across a load but not conducting wires?
as the resistance/impedance of the the conducting wire is so small as compared to the load, there is a very low voltage drop across the conducting wires. keep the Ohm's law in mind i.e. V=IR <><><> Agree- but making the conducting wires LONG enough, and there will be enough resistance for a voltage drop.
What is the meaning of IR of voltage?
In Ohm's Law, E stands for voltage, I stands for current (amps), and R stands for resistance. Ohm's Law states: E = IR or voltage equals current times resistance. This means that current flowing through a wire (that has resistance) produces a voltage drop in the wire. Since the voltage drop is the result of current flowing through a resistance, old-school engineers will sometimes refer to it as "IR drop". So, since E = IR, saying "IR" is the same as saying "voltage".
If resistance decreases then power?
Resistance is decreases then the voltage drop across it is decreases because of ohms law (V=IR),due to this power can also be decreases because of P=VI. so finally we can say that resistance decreases ,power also decreases.
If you add the IR drop or voltage drop of each individual resistance in a series circuit is it equal to the applied voltage?
Yes
Why does higher resistance have a larger voltage drop across it?
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
How much resistance is required to limit the current to 1.5 mA if the potential drop across the resistor is 6V?
Using ohm's law, V=IR then R=V/I =6/0.0015=4000 ohm = 4k ohm resistor.
How does voltage drop related to impressed emf?
Voltage drop is resultant of IR ie current and the line resistance, not dependent on impressed emf
How do you calculate internal resistance?
You need to use the formula E = IR + Ir where: E is the e.m.f. of the power supply (the theoretical maximum voltage across the terminals when no current is flowing) I is current R is resistance of the circuit (load resistance) and r is the internal resistance of the power supply. Therefore, you can rearrange this formula to give r: E = IR + Ir (Subtract IR) E-IR=Ir (divide by I) (E-IR)/I=r or r=(E-IR)/I
