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Losses due to the local disturbances of the flow in the conduits such as changes in
cross section, projecting gaskets, elbows, valves and similar items are called minor
losses. In other words, the losses that occur in pipelines due to bends, elbows, joints, valves, etc. are sometimes called minor losses.In case of a very long pipe, these losses are usually insignificant in
comparison to the fluid friction in the length considered. But In case of short pipes,
these minor losses may actually be major losses such as in suction pipe of a pump
with strainer and foot valves.
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What current Must flow if 0.24 coulombs is to be transferred in 15Ms?
For a steady flow of charge through a surface, the current I in amperes can be calculated with the following equation:I = Q/t where Q is the electric charge transferred through the surface over some time t. If Q and t are measured in coulombs and seconds respectively, I is in amperes. Thus: I = 0.24 coulombs / 15 msec I = 0.24 coulombs / 15 * 10^-3 sec I = 16 amps
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How can you calculate the flow of FD fan and motor power when you know fan speed and impeller diameter?
times by 2
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In the Bernoulli's theorem demonstration how can you improve the accuracy of the results?
we can improve the bernoulli equation by adding the head losses at the final flow state and also we account the major (friction loss and viscus loss) losses and Minor losses (pipe bend , pipe contraction , pipe inlet and outlet, pipe fittings , valves etc)... If we account those losses and added to the head losses then the Bernoulli's equation gives the very accurate value....
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