The chance of a diabetic baby born to parents who are both heterozygous normal depends on the sex. If the baby is a boy, there is a 50% chance while if it is a girl, there is a 25% chance.
the boy has 50% chance adn the girl has 25%
1/4
Yes. Two normal-visioned parents can produce a color blind child only if both the parents have are heterozygous. To determine the phenotypes of the parents, you will have to look at their parents.
The genotype would have to be homozygous recessive if the child was completely effected by the disease. The "normal" paretns would have to have heterozygous recessive genotypes. This makes sense since the allele that causes sickle cell shows incomplete dominance when present with a normal allele in a pair. The "normal" parents actually would have a mixture of sickle cell shaped red blood cells combined with normal shaped ones. The carrier parents does not display symptoms of the disease since the regular red blood cells alone can fill the body's need for oxygen under normal circumstances. The only time the cArrier would notice would be under times of extreme oxygen demand, such as a sprint.
Yes, because Hemophilia is recessive (if you have a normal allele, you won't have hemophilia, and heterozygous means that you have one normal and one abnormal allele).
The Overo allele is only lethal when the foal inherits a copy from both parents. A heterozygous foal is a normal frame overo.
The normal blood sugar for a non-diabetic person is below 5.7%. If you do not have this and you haven't been diagnosed as an diabetic, go to your doctor and they will advise you on how to proceed.
It depends on the genotype of the childs other parent. If your partner is heterozygous as well then there is a 25% chance your child will be homozygous recessive. If they are homozygous dominant then none of your children will have the phenotype of the recessive trait. They will just possibly be carriers of the recessive allele.
malaria
Yes, though it's rare. For each child the odds of that happening genetically is 25%) so to calculate the odds of n children of heterozygotic parents having that condition would be (1/4)n
Fyugugy
If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.
Yes!
If both parents are just carriers of the gene that causes CF then there is a 75% chance that the child will not have CF. To break it down farther... 25% chance that they will have CF. 50% that they will be a carrier. 25% that they will have two normal genes.