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What is the effect of internal resistance of the source to its output voltage?
Wiki User
∙ 12y ago
(a) It reduces the amount of current.
(b) Any current that does pass the resistor will lose some power; this lost power is converted to heat in the resistance.
AnswerInternal resistance acts to reduce the terminal voltage of the voltage source when it supplies a load. This is due to the internal voltage drop caused when the load current passes through the internal resistance of that source. The greater the load, the lower the resulting teminal voltage.
By definition, a voltage source's electromotive force is equal to the sum of the voltage drops, including the internal voltage drop, of the circuit supplied.
Wiki User
∙ 12y ago
Wiki User
∙ 12y agoWhen a load current flows, as well as flowing through the load, it also flows, internally, through the voltage source. A load current, therefore, causes an internal voltage drop which, by Kirchhoff's Voltage Law, opposes, the electromotive force of the source. The larger the load current, the greater the internal voltage drop.
So, the terminal voltage of a voltage source will decrease as the load current increases.
By definition, the e.m.f. of the source is equal to the sum of all the voltage drops (including the internal voltage drop) around any closed loop supplied by that source.
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What is the effect of change in load resistance on output voltage?
No.
Why during loading the voltage get decreased at output?
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
What is Impedance of ideal voltage source?
An ideal voltage source has no internal resistance, and a constant voltage output. In reality, all voltage sources (battery, generator, etc.) have some internal resistance, and their voltage may degrade or change over time.Ans 2: An ideal voltage source will have zero input impedance and the voltage can rise to infinity to supply the current.Read more: What_does_an_ideal_voltage_controled_voltage_sources_do
What is the effect of diode voltage drop as the output voltage?
The effect of diode voltage drop as the output voltage is that the input voltage will not be totally transferred to the output because power loss in the diode . The output voltage will then be given by: vout=(vin)-(the diode voltage drop).
Why might the unloaded output voltage of a transformer be higher than its rms of 12.6v?
Because the windings of transformers have resistance, the primary and secondary currents will cause voltage drops. To compensate for the drops, the transformer may have been designed to have a higher than specified output voltage when there is little or no output current. The no load output voltage typically is only slightly greater than the specified voltage. Before measuring the output voltage, measure the input (line) voltage. If it is not as specified for the transformer, calculate its effect on the output.
What is the effect of change in load resistance on output voltage?
No.
Why during loading the voltage get decreased at output?
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
The no-load output voltage of a DC power supply is measured at 15V When a 600 ohms load is connected to the output the output drops to 13.7V Calculate the internal resistance of the power supply?
This question can be answered using voltage dividers. Assume the power supply consists of a voltage source and a resistor. With no load, all of the voltage source's voltage is dissipated by the internal resistor of 15V. When there is a load, there are two resistors in series. To calculate the internal resistance:1. I=V/R. You know the 600ohm resistor dissipated 13.7V. So that would mean a current of 13.7/600=22.8mA2. If the 600ohm resistor dropped 13.7, kirchoff's voltage law would tell us the internal resistor dropped 15-13.7=1.3V.3. R=V/I, Use the current to calculate the internal resistance. 1.3/22.8mA = 56.9ohmsCommentFurther to the above answer, a voltage-source's voltage is not 'dissipated by the internal resistance when on no load'. On no load, there is no current passing through the internal resistance, so no 'voltage dissipation' can takes plac -i.e. the non-load voltage is 15 V.
What is Impedance of ideal voltage source?
An ideal voltage source has no internal resistance, and a constant voltage output. In reality, all voltage sources (battery, generator, etc.) have some internal resistance, and their voltage may degrade or change over time.Ans 2: An ideal voltage source will have zero input impedance and the voltage can rise to infinity to supply the current.Read more: What_does_an_ideal_voltage_controled_voltage_sources_do
Input resistance and output resistance of Voltage series feedback amplifier?
output resistance decreases and input resistance increases
A measure of how strong a battery or power source is?
A good measure is its internal resistance. If the internal resistance was 1 ohm, the output voltage would fall by 1 volt for every amp of current taken. So - how low is the internal resistance? is a good question to find out how strong the source is.
What is the effect of diode voltage drop as the output voltage?
The effect of diode voltage drop as the output voltage is that the input voltage will not be totally transferred to the output because power loss in the diode . The output voltage will then be given by: vout=(vin)-(the diode voltage drop).
In what way the connections are made to get a higher output current from light?
A light doesn't output current, it "draws" current based on voltage and its resistance. Voltage = Current x Resistance or Current = Voltage / Resistance. (Ohm's Law)
What is the use of offset null pin in integrated circuits?
Pin used to eliminate the effect of internal component voltage on the output of the device.
Batteries have what current?
Battery maximum current is limited by the internal resistance of the battery. As the current is increased towards this maximum, you will notice the output voltage appear to shink towards zero. What this means is the voltage the battery is capable of supplying is being dropped almost completely across the internal resistance, so no real power is available to use.This internal resistance is dependent on the chemical and physical makeup of the battery.
What is the difference between ideal and practical voltage source?
An ideal voltage source is a theoretical concept used in electrical engineering and circuit analysis. It is a voltage source that maintains a constant voltage output regardless of the current flowing through it or the load connected to it. In other words, an ideal voltage source has zero internal resistance and can supply infinite current at a constant voltage. In contrast, a practical voltage source is a real-world device that has internal resistance and cannot maintain a constant voltage output when a load is connected to it. The voltage output of a practical voltage source will decrease as the current flowing through it increases, due to the internal resistance of the source. As a result, the voltage across the load will be less than the voltage output of the source, and the difference is known as the voltage drop. In practical applications, it is important to take into account the limitations of practical voltage sources and design circuits that can operate within these limitations. An understanding of the behavior of both ideal and practical voltage sources is essential for designing efficient and effective electrical circuits. You also read more at electronicsinfos. com
Why might the unloaded output voltage of a transformer be higher than its rms of 12.6v?
Because the windings of transformers have resistance, the primary and secondary currents will cause voltage drops. To compensate for the drops, the transformer may have been designed to have a higher than specified output voltage when there is little or no output current. The no load output voltage typically is only slightly greater than the specified voltage. Before measuring the output voltage, measure the input (line) voltage. If it is not as specified for the transformer, calculate its effect on the output.
