A condensed (or abbreviated) electron configuration is a way to draw an orbital diagram for a late electron. For this type of diagram the core electrons are replaced with the symbol for the noble gas nearest to the element you are describing. Brackets are put around this symbol and then the outer, valence electrons are described as usual.
Long-hand version: 1s^2 2s^2 2p^6 3s^1 Short-hand version: [Ne] 3s^1 Note: The "^" symbol means the the following number is in the form of a superscript.
the electron configuration formula is 2n2. If nrepresents the energy level/shell number, the first shell would have 2 x 12 = 2, then 2 x 22 = 8, etc.
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
Let us assume that we have Sodium (Na), it has the ground state electron configuration of: [Ne]3S1. The ANION is negative, and thereby has more electrons, the Na anion(Na.) would have the following electron configuration: [Ne]3S2. The CATION(which is a positive ion) of Na(Na+) would have [Ne] as it electron configuration(as it loses an electron and becomes "equal" to Neon)
N3- , O2- , F- , Na+ , Mg2+ , Al3+ all have the same electron configuration as Neon.
The electron configuration of sodium is: [Ne]3s1.
The electronic configuration for the sodium ion, Na+ is 1s2 2s2 2p6 or [Ne]
In NaF, there exists Na+ and F- ions and with the electron configuration of [He]2s22p6 (for Na+) and [He]2s22p6 (for F-)
In NaCl, there exists Na+ and Cl- ions and with the electron configuration of [He]2s22p6 (for Na+) and [Ne]3s23p6 (for Cl-)
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
Let us assume that we have Sodium (Na), it has the ground state electron configuration of: [Ne]3S1. The ANION is negative, and thereby has more electrons, the Na anion(Na.) would have the following electron configuration: [Ne]3S2. The CATION(which is a positive ion) of Na(Na+) would have [Ne] as it electron configuration(as it loses an electron and becomes "equal" to Neon)
neon
Na+ is the formula of the ion formed when sodium achieves a stable electron configuration.
N3- , O2- , F- , Na+ , Mg2+ , Al3+ all have the same electron configuration as Neon.
The electron configuration of sodium is: [Ne]3s1.
The electronic configuration for the sodium ion, Na+ is 1s2 2s2 2p6 or [Ne]
Na+ ion.
Neon has the same electron configuration as Na+ ion
Sodium in all its compounds forms the Na+ ion.Its electron configuration is the same as of noble gas Ne:(Na+) = (1s2, 2s2 2p6, 3s0)Na2+ would have the following electron configuration: 1s2, 2s2 2p5This is not a noble gas configuration and requires a lot of energy to remove the 2nd electron out off the 2px orbital just after the 1st removal from its 3s orbital. It only is observed for example as a transient species when sodium vapour is irradiated with strong laser light.