The two will react to form salt and water
HCOOH (aq)+ KOH(aq) --> HCOOK(aq) + H2O(l)
In ionic form,
HCOOH + K+ + OH- --> HCOO- + K+ + H2O
HCOOH is weak acid so it should not be written in ionic form.
K+ ions cancel out leaving
HCOOH + OH- --> HCOO- + H2O (net ionic equation)
HNO2 + KOH -------> KNO2+ H2O
HNO2 +KOH -------> KNO2-+ H2O
HNO2 (aq) + K+ (aq) + OH- -------> K+ (aq) + NO2- (aq) + H2O (l)
HNO2 (aq) + OH- (aq) -------> NO2-(aq) + H2O (l)
Balanced equation: CH3COOH + KOH --> CH3COOK + H2O
Total Ionic Eq.: CH3COOH + K+ + OH- --> CH3COO- + K+ + H2O
and leaving K+ out on both sides, because they are unchnged (socalled 'tribuned') gives you the:
Net Ionic Eq.: CH3COOH + OH- --> CH3COO- + H2O
(Extra remarkable: The acetic acid is not 'written' in ions, because it is a weak acid: only much less than 0.1% is ionised, potassium acetate however is fully (100%) ionised in aqua)
KOH(aq) + CH3COOH(aq) ==> CH3COOK(aq) + H2O(l) ... complete molecular equationK^+(aq) + OH^-(aq) + CH3COOH(aq) ==> CH3COO^-(aq) + K^+(aq) + H2O(l) ... total ionic eq.
OH^-(aq) + CH3COOH(aq) ==> CH3COO^-(aq) + H2O(l) ... net ionic equation
The net ionic equation for potassium hydroxide and phosphoric acid should look like the following: H3PO4 + 3OH- --> PO4^3- + 3HOH(l).
H+(aq) + OH-(aq) ----> H2O(l)
The chemical reaction is:NH4ClO4 + KOH ↔ KClO4 + NH4OH
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
2H3O+(aq) + Ca(OH)2(s) -> 4H2O(l) + Ca2+(aq)
There is no reaction, therefore no equation!!
H+(aq)+OH−(aq)→H2O(l)
Potassium plus Water gives Potassium Hydroxide plus Hydrogen
Lithium + water = lithium hydroxide + hydrogen Sodium + water = Sodium hydroxide + hydrogen Potassium + water = Potassium hydroxide + hydrogen
H2SO4 + 2KOH = K2SO4 + 2H2O
HCl + KOH ==> KCl + H2O
Water.
K and ClO4
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
Stearic acid reacts with potassium hydroxide to form water and potassium stearate. The reaction equation is C18H36O2 + KOH = C18H35O2K + H2O.
No reaction.
The chemical reaction is:NH4ClO4 + KOH ↔ KClO4 + NH4OH
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
The stated reaction is an example of a neutralization reaction between an acid and a base forming a product salt and water. The equation of the reaction is HNO3 + KOH -> KNO3 + H2O.