Mass% is the ratio of elements in a given quantity.
if you mix 20 parts of A with 30 parts of B
you will have a solution with 50 parts AB
so take the quantity of A (20) and divide it by the total volume (50) and multiply by 100. This means you have 40% of A in your solution.
likewise with B (30/50) x 100 = 60% by mass
before not to confuse %mass with mole ratio as this is significantly different
20 per cent by mass means 20 per cent by weight. The contents of a mixture are usually expressed as percentages by volume, but it sometimes makes more sense to describe it by weight.
It doesn't really make too much sense to use a percentage by mass. The difference between mass and weight is only significant when the gravitational field is not constant. Even if the gravitational field were to vary across the mixture, any part of it would still have the same composition, whether measured by mass or by weight.
Example: sodium chloride, NaCl
1. Search the atomic masses of sodium and chlorine in chemical tables;
Na - 22,989 769 28 and Cl - 35,45 (abridged).
2. Calculate the molecular mass of NaCl: Na + Cl = 58,43976928 = 58,44 (abridged)
3. Calculate the percentage of sodium:
58,44 g NaCl--------------22,99 g Na
100 g NaCl----------------x
x = 22,99.100/58,44 = 39, 34 % Na
4. Calculate the percentage of chlorine:
100 - 39,44 = 60,56 % Cl
Percent mass = (Mass solute/Mass solution) X 100%
This is the concentration of a component in a material expressed in mass percentage.
Example: a type of coal has 15 % ash. The meaning is 15 g ash in 100 g coal.
(Mass of Solute/Mass of Solution)X 100%
soso na malaki
AgCl
Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.
((mass of element)/(mass of compound))*100
ch2o and c6h12o6
Firstly divide percentages by molar mass of that elementNa43.4/23=1.9C11.3/12.01=0.94O45.3/16=2.83Then divide the result of the first step by the smallest answerNa1.9/.94=2C.94/.94=1O2.83/.94=3Empirical Formula is Na2CO3
gaga si cherywel
% of volume = 100*(volume of substance that you are interested in)/(total volume) % of mass = 100*(mass of substance that you are interested in)/(total mass).
Cr3Si2 is the empirical formula for a compound containing chromium and silicon an has 73.52 mass percent chromium.
HClO3 (gram-formula mass = 84 g/mol)
The formula of the compound and the Atomic Mass of its elements.
CaBr2 :)
AgCl
Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.
The formula of ammonium sulphate is (NH4)2SO4, showing that each formula mass contains one sulphur atom. The formula mass of ammonium sulphate is 132.13, and the gram atomic mass of sulphur is 32.06. Therefore, the percent by mass of sulphur in ammonium sulphate is 100(32.06/132.13) or 24.26, to the justified number of significant digits.
((mass of element)/(mass of compound))*100
ch2o and c6h12o6
BrO2