# What is the rest of this number pattern 243 81 27 9 and you need two more?

# The next number in the series 1 3 9 27 81?

its an exponential series. 3^0=1 3^1=3 3^2=9 3^3=27 3^4=81 3^5=X more of how to solve it then the answer [if your still stuck think of it as 81x3=X].
in laymans terms 243, times it by 3 each time.

# What are the next 2 numbers in this pattern 64 243 256 125?

So the pattern would be 0 up to the 8 which equals 0. Next would be1 up to the 7th which equals 1. Next the sequence would be 2 up tothe 6th which equals 64, 3 up to the th5 which equals 243, 4 up tothe 4th which equals 256, 5 up to the 3rd equals 125, 6 up to the2nd equals 36, 7 up to the 1st equal…s 7, and 8 up to the 0 equals1. (MORE)

# What is the next number in the pattern 27 9 3 1?

The numbers are being divided by one third each time. therefore, after 1 comes 1/3 or one third.

# What is the least common factor of 81 and 243?

The factors of 81 are 1, 3, 9, 27, and 81. The factors of 243 are 1, 3, 9, 27, 81, and 243. The common factors of 81 and 243 are 1, 3, 9, 27, and 81. Therefore, the least common factor (the smallest common factor) is 1.

# Find the pattern to 1 9 25 49 81 121 169?

It is a sequence of squares of odd numbers starting from 1 1x1=1 3x3=9 5x5=25 7x7=49 and so on

# What is the pattern for 729 243 81 27?

They are powers of 3. 729 = 3 6 243 = 3 5 81 = 3 4 27 = 3 3 9 = 3 2 3 = 3 1

# What is the odd number out 16 36 64 27 81?

The only number in that list which is not a square number is 27. 27 is a cube number.

# What are the next two numbers in this pattern 6 13 27 55?

6,13,27,55, 111, 223 ... .
Here is why:.
6 + (1x7) makes 13.
13 + (2x7) makes 27.
27 + (4x7) makes 55.
55 + (8x7) makes 111.
111 + (16x7) makes 223.
Or this way explains the answer using powers of 2:.
(7x2 0 )-1 makes 6.
(7x2 1 )-1 makes 13.
(7x2 2 )-1 makes 27.
(7x2 3 )-1 makes 55.
(7x…2 4 )-1 makes 111.
(7x2 5 )-1 makes 223 (MORE)

# Math rule for 1 3 9 27 81?

I don't know exactly what type of formula you are looking for......
But, if you let n = # of term.... then the rule would be 3^(n - 1)

# What is the pattern for 81 27 9?

Each number is one third of the previous number, the next number in the series would be 3

# What number comes next in this pattern 3 9 81 6561?

The numbers are being squared:.
3 2 = 9.
9 2 = 81.
81 2 = 6561.
6561 2 = 43046721

# What are two ways to write the number 81?

9 to the 2nd power (9 2 ) 3 to the 4th power (3 4 )

# The numbers 81 27 and 45 are what multiples?

They are all multiples of 9. Their common multiples are 405, 810, 1215 and so on.

# What is the next number in the pattern 1 8 27 64?

The next number in the pattern is 125 . This pattern is determined by cubing the numbers. First number = 1 x 1 x 1 = 1 Second number = 2 x 2 x 2 = 8 Third number = 3 x 3 x 3 = 27 Fourth number = 4 x 4 x 4 = 64 Fifth number = 5 x 5 x 5 = 125 etc.

# Which is the odd number 16 36 64 27 81?

27 and 81 are the odd numbers. Since odd numbers are 1, 3, 5, 7 and 9, look at the last number and you will be able to tell if it's odd or even.

# What number comes next in the sequence 243 81 27?

9 243 - 81 = 162 81 - 27 = 54 162 = 54 * 3 54 = 18 * 3 27 - 18 = 9

# What sum of two numbers is 27 the second number is one more than the first?

say the two numbers represent x and y x + y = 27 x + 1 = y therefore if you substitute the second equation into the first equation of x (y +1) + x = 27 2x + 1 = 27 2x = 26 x= 13 y= 14

# What is the next number in the following series 3 9 27 81 243?

729 is the next number in the sequence. You times each number by the past number times by three e.g. 3x3=9, 9x3=27, 27x3= 243, 243x3=729

# What two numbers go into 81?

1 and 81 Those two numbers certainly divide into 81 though they are not the only numbers to do so.

# Can you help me find the next two numbers in this number pattern3 9 27 81?

Each number is 3 times the previous number, so the next two numbers are 243 and 729: 3 x 81 = 243 3 x 243 = 729

# What is the pattern 1 3 9 27?

t(n) = 3 (n-1) .....also means that you multiply each number by 3 to get the next number

# Why are 1 3 9 27 divisible by 81?

They're not. 81 is divisible by 1, 3, 9, 27, and 81. Those are called the "factors" of 81, because each of them divides evenly into 81 with no remainder.

# The mean of nine numbers is 27 and if two of the numbers 94 and 163 are taken out of the set of 9 numbers what will the mean of the remaining 7 numbers be?

So, we already know that the mean of the nine numbers is 27. We'll have to do 27 times 9 to know what the nine numbers add up to be. The answer is 243. the numbers that are taken out are 94 and 163. so we'll have to do 243-94=149 Then you do 149-163=-14 You know there is 7 remaining numbers so you …do -14/7 and you get -2. So the answer is -2!!!!!! (MORE)

# What two numbers equal 81?

There is only one number that's equal to 81. That number is 81. There are many other sets of two or more numbers that you can manipulate with an arithmetic operation and produce 81 as the result. For example: Addition: 27 + 54 = 81 Subtraction: 175 - 94 = 81 Multiplication: 3 x 27 = 81… Division: 567 / 7 = 81 But none of those other numbers is "equal" to 81. (MORE)

# What are the next two numbers 1 3 9 27?

t(n) = 3 n-1 , where n = 1, 2, 3, ... t(5) = 81 t(6) = 243

# What is the answer to this number sequence 81 27 9 3 1?

Each number is found by dividing the previous number by 3. The next number would be a fraction called "one third", and then "one ninth" and so on.

# What is the next pattern of 3 9 27 81 243 729?

9 divided by 3 is 3. So 9 times 3 is 27. Now that we know the pattern is times 3, just go to the last number and multiply by 3 to get 2187

# What is the LCM of 9 27 and 81?

81; each number is a factor of 81, and it is the smallest you can get.

# What are the multiples of 9 81 and 27?

Well this is a very tricky question If you mean a number that they can all go into . The smallest would be prime factorization helps 9 = 3 x 3 81= 3 x3x3x3 27 = 3x3x3 largest number of 3's is 3 to the 4th exponent which would equal 81. They can all go into 81 to find the next number multiply …by 3 again and so on. (MORE)

# What are the next two numbers 729 243 81 27 9?

The given sequence is Geometric Progression. Ratio of any term to its preceding term is 1:3 so common ratio is 1/3 i.e. r = 1/3. First term is 729 i.e. a = 729. Now, we need to find the sixth and seventh terms. nth term of a G.P. is given by a n = ar n-1 . So, a 6 = 729 x (1/3) 6-1 = 729/…243 = 3. a 7 = 729 x (1/3) 7-1 = 729/729 = 1. (MORE)

# What number comes next in this pattern 3 9 81 6 561?

There should only be four numbers in the question: 3, 9, 81 and 6561. Then the fifth is 43046721.

# What two numbers multiplied equals 243?

243 has a decent number of factors (1, 3, 9, 27, 81, 243), so you have a few choices. The most obvious one is simply 243 * 1 = 243. 3 * 81 and 9 * 27 also work.

# Why does the fact family for 81 and 9 have only two number factor?

The fact family for 81 has more than 2 factors: 1, 3, 9 are factors: and that is more than two!

# What are two numbers having a gcf of 9 and a sum of 99what is the gcf of all of the numbers in the pattern 12 24 36 48?

Please ask these as separate questions next time. The numbers are 81 and 18 or 9 and 90 or 27 and 72. The GCF is 12.

# What is a number pattern in multiples of 9?

The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.

# What numbers is not divisible by 9 81 162 199 1125?

81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 Ã¢Â†Â’ 1 + 9 = 10 Ã¢Â†Â’ 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9,… so 1125 is divisible by 9. So 199 is the only one not divisible by 9. (MORE)

# What are the next two numbers in this pattern 27 22.5 18 13.5?

They are reducing by 4.5 each time. So the next two numbers are 9and 4.5 after that.

# What is the missing number of this pattern 7 16 8 27 9?

The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY… position..
Using polynomials of order 4, though, there is only one answer for each position. For example,.
First number missing: 171.
U n = (-27n 4 + 422n 3 - 2364n 2 + 5611n - 4668)/6.
Last number missing: 218.
U n = (-27n 4 + 314n 3 - 1260n 2 + 2041n - 1026)/6.
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position..
Using polynomials of order 4, though, there is only one answer for each position. For example,.
First number missing: 171.
U n = (-27n 4 + 422n 3 - 2364n 2 + 5611n - 4668)/6.
Last number missing: 218.
U n = (-27n 4 + 314n 3 - 1260n 2 + 2041n - 1026)/6.
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position..
Using polynomials of order 4, though, there is only one answer for each position. For example,.
First number missing: 171.
U n = (-27n 4 + 422n 3 - 2364n 2 + 5611n - 4668)/6.
Last number missing: 218.
U n = (-27n 4 + 314n 3 - 1260n 2 + 2041n - 1026)/6.
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position..
Using polynomials of order 4, though, there is only one answer for each position. For example,.
First number missing: 171.
U n = (-27n 4 + 422n 3 - 2364n 2 + 5611n - 4668)/6.
Last number missing: 218.
U n = (-27n 4 + 314n 3 - 1260n 2 + 2041n - 1026)/6. (MORE)

# What is the pattern 1 3 9 27 81?

x i+1 = 3 x i x 1 = 1 x 2 = 3 x 1 = 3 x 3 = 3 x 3 = 9 x 4 = 3 x 9 = 27 x 5 = 3 x 27 = 81

# What is the prime factorization of 243 written as a factor of two numbers?

The prime factorization of 243 will require 5 numbers. It is possible to write a factorization in two numbers, but they won't both be prime. 3 x 3 x 3 x 3 x 3 = 243 9 x 27 = 243

# How do you arrange 1 3 9 27 81 243 729 2187 6561 19683 59049 177147 5314411 594323 4782969 14348907 on a 4x4 grid so the sum of the rows and columns are equal?

You cannot. The sum of all 16 numbers is 21,523,360. Since this sum is partitioned into four equal rows, each row must sum to 21,523,360/4 = 5,380,840. However, the last number, 14,348,907 is larger than 5,380,840. The sum of four positive numbers cannot be smaller than one of those numbers. Conse…quently the task is impossible. (MORE)

# Why does the fact family for 81 ad 9 have only two number sentences?

It has only 2 numbers: 9 and 81. Since 9 squared (9^2, 9*9). So all there is is: .
9 ÃƒÂ— 9 = 81 .
81 = 9 ÃƒÂ— 9

# What two numbers can go into 81?

9 x 9 = 81 These numbers go into 81: 1, 3, 9, 27, 81.

# Is the pattern 1 3 9 27 arithmetic?

No it is not. It is most likely to be geometric t(n) = 3^(n-1) for n = 1, 2, 3, 4. But it is equally possible that the sequence is generated by the following order 4 polynomial: t(n) = (15*n^4 - 118*n^3 + 381*n^2 - 494*n - 240)/24 for n = 1, 2, 3, 4. Or infinitely many other polynomials.

# What number is after 81 in the pattern 1 9 9 81 81 if the pattern is by 9's and 1's?

There are at least three possible answers, consistent with the information given in the question. Short of reading the mind of the person who posed the question, there is no way of determining which of these (or other) solutions is the "correct" one. Answer A: It is 81. The sequence is 1 followed b…y 2 lots of 9^1, then 3 lots of n^2, then 4 lots of n^3, etc. Answer B: It is 729. The sequence is 1 followed by pairs of powers of n. Answer C: It is 6561. The sequence is 1 followed by a pair of 9s, followed by a pair of 9^2, followed by a pair of (9^2)^2, then ((9^2)^2)^2, etc. (MORE)

# The larger of two numbers is 9 more than four time the smaller number. the sum of the two numbers is 64. find the two.?

Let the smaller number be y. Then the larger number is 4y + 9 The sum of the numbers is 64 so > y + (4y + 9) = 64 > 5y + 9 = 64 > 5y = 55 > y = 11 so the other number of 53. 11 and 53 are the two numbers

# What is the number pattern for 243 81 27 and 9?

Each number is 1/3 the value of the one to the left. The nextnumber in the series is... 3.

# What other multiple besides 9 are multiples of 81 27 and 45?

1, 3 and 9 are common factors of 27, 45 and 81. 27, 45 and 81 are multiples of 1, 3 and 9.

# What is the next number to follow series 1 3 9 27 81?

243 each number is 3 times larger than previous 1 x 3 = 3 3 x 3 = 9 9 x 3 = 27 27 x 3 = 81 81 x 3 = 243

# How do you find the nth term for the sequence 3 9 27 81 243?

The nth term is found by multiplying the first term by the commonratio to the n minus one power. In this case, that turns out to be 3 x 3^n-1