Want this question answered?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl
hic noah
NaCL + H2O
NaCl
nacl
NaOH and HCl are the reactants; water and ammonium chloride are the products.
This equation is Na2CO3 + 2 HCl -> 2 NaCl + CO2 (gas) + H2O.
carbon dioxide
NaCl and H2O
An acid-base reaction
The product of this reaction is salt:NaOH + HCl = NaCl + H2O