Electron configuration for oxygen (O) is 1s2 2s2 2p4. The valency is 2-.
The electronic configuration of oxygen is: [He]2s2.2p4.
By the formula 2n2 , we can find no of electrons in shells like, if atomic no. of X is 17 so the electronic configuration is 2,8,7. so the valency is 1 in order to complete its octave.
As Barium's atomic number is 56 and as it has 2 electrons in its outer shell (this is also due to the fact that it is in Group 2) its valency is 2. It loses 2 electrons to attain the electronic configuration of Xenon whose atomic number is 54, so it is electropositive and is a metal.Therefore its valency is 2+. As Barium's atomic number is 56 and as it has 2 electrons in its outer shell (this is also due to the fact that it is in Group 2) its valency is 2. It loses 2 electrons to attain the electronic configuration of Xenon whose atomic number is 54, so it is electropositive and is a metal.Therefore its valency is 2+.
it does. for example in H2O oxygen has a valency 2 while in hydrogen peroxide H2O2 oxygen exhibits valency 1
Oxygen receives 2 electrons, so it has the electronic configuration like neon.
The electronic configuration of Calcium is 2-8-8-2, therefore the valency of Calcium is +2.
The electron configuration of oxygen is 1s22s22p4.
The electronic configuration of oxygen is: [He]2s2.2p4.
because the valency is no of electrons present in last shell and different element have different electronic configuration.
Valency is calculated in this way... 1. Find atm no of that element. 2. Write down electronic configuration. 3. Take the valence shell electron number. 4. The number of electrons to be lost are added as the valency.
Titanium has (max.) 4 valence electrons, possible oxidation states: +4, +3, +2, (+1, rare).
6. Oxygen has an electronic configuration of [He]2s22p4
The number of electrons on the external level is generally equivalent to valency.
Oxygen has 2 as its valency.
By the formula 2n2 , we can find no of electrons in shells like, if atomic no. of X is 17 so the electronic configuration is 2,8,7. so the valency is 1 in order to complete its octave.
Oxide - O2- electronic configuration of oxygen atom: 1s2, 2s2 2p4. electronic configuration of oxygen ion: 1s2, 2s2 2p6. phosphate - PO43-
This is because in nitrogen the 2p subshells are filled by 3 electrons which is half filled electronic configuration. But oxygen has to lose an electron to attain the half filled electronic electronic configuration. Hence nitrogen is more stable than oxygen.