The "size" (value or the power capacity) of the resistor can not be defined unless the power of the 3 volt bulb is known. If you tell me how many amps would the bulb draw from a 3 volt source, I will tell you exactly how many ohms of resistance, and how many watts of power capacity will be required of the resistor.
The voltage drop is equal to the current in amps times the ohms. For a constant-current load just divide the voltage-drop by the current to find the necessary resistance in ohms. For a varible load a simple voltage regulator should be used.
cannot determine without other information not given.
using a voltage regulator would be the better way to go
You will need to take the resistance of the load into account if you are going to design a voltage divider. The resistance of the load can completely change the voltage ratio of a voltage divider if not factored into the calculation. you can measure or read R(load), then R(needed) = 0.8 R(load)
Greater value resistor will absorb more voltage than smaller value. The more voltage absorb with same value current flow, the larger body mass resistor will require. Body size depends on type of resistor (material resistor is made of).
The formula which are needed for making of a single phase transformeri.e o/p voltage,watt,current,turn,core size,coil number,bobin size etc
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
You need also to know the resistance of the cable. First you establish what the current of the load is. Then from that you calculate the wire size. From a wire size chart you find the wire resistance. Then use the formula I (squared) x R.
Its dependent what will by rated power of the device (current).
use Ohm's law: to drop 2 volts, V = I x R 2 = current x resistance resistance = 2 / current. So you need to know the current
This question cannot be answered because you did not specify the current.
If there is nothing else in the circuit, then the voltage drop across the resistor will be the full supply voltage of 5 volts. The size of the resistor does not matter in this case - it will always be 5 volts.
it is better to use zener diodes or transformators in order to drop 12 vdc to 2 vdc. If you do it with resistor you will waste you power. Voltage formula for resistors in series V1+V2+........+Vn=Vtotal, so 2Vdc+i.R=12Vdc. Determine the current for you supplier and calculate the value of resistance.
You will need to take the resistance of the load into account if you are going to design a voltage divider. The resistance of the load can completely change the voltage ratio of a voltage divider if not factored into the calculation. you can measure or read R(load), then R(needed) = 0.8 R(load)
330 milli ohms
It doesn't work that way. An oxygen sensor can not be bypassed.
A resistor in parallel with a voltages source will not cause the voltage to drop, theoretically. To get a 20 volt drop you need a resistance in series, and the number of ohms is 20 divided by the current in amps. If the current is unknown or variable, the voltage can't be dropped by using a resistor.
There is no relation between the resistor's ohms value and its size. The power of the resistor can be seen by its size. If the power is too small, the resistor can be destroyed.
Greater value resistor will absorb more voltage than smaller value. The more voltage absorb with same value current flow, the larger body mass resistor will require. Body size depends on type of resistor (material resistor is made of).
there might be ways to get the power rating by measuring the size of the resistor. but as the physical size of the resistor increases, its power rating also increases..