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When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R.

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A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage.

In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source

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13y ago
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13y ago

Because the resistors are in series, the current flow will be uniform through them all. I (in amps) = E (in volts)/ R (in ohms) where R is the sum of the resistances, including the resistance of the wires connecting the circuit. The voltage drops across them will sum to equal the voltage applied to the circuit, with perhaps a small drop across the conductors.

The voltage drop across each resistor will be exactly enough to cause this value of current to flow through each resistor.

If they were wired in parallel, the voltage drop across each would be the same and the currents would vary based on the resistance of each leg of the circuit.

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11y ago

The voltage drop across each parallel resistor remains the same. However, the current is devided amongst the resistors by the size of each resistor. As the ohmic value deceases the current increases.

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13y ago

For each individual resistor,

(voltage across it) divided by (current through it) = the resistor's value.

When resistors are connected in parallel, the voltage across each individual resistor

is the same as it is across all of the others, and the currents through each individual

are in the same ratio as the reciprocals of their resistances.

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Q: When resistors are connected in series in a circuit. what are the relationships between the voltage drops across the resistor and the currents through the resistors?
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