Take the example of a satellite moving around the earth:
In this case, the satellite is moving in a circular path and the centripetal force is provided by the gravitational force of the earth. At every point in the circular path, the centripetal force acts at right angles to the direction of motion of the satellite, i.e. the force and displacement are perpendicular to each other.
therefore Ɵ = 90 0
W= Fs cos Ɵ
= Fs cos 900
= Fs 0
=0
Yes. A force acting on a body in the direction of its motion does work. The formula for work is W = F x d, where force(F) is in Newtons, distance(d) is in meters, and work(W) is in Newton*meters(N*m), or Joules(J). (1N*m = 1J)
Only the component of movement in direction of the force is calculated - in other words, the work is equal to the force, times the distance, times the cosine of the angle between the two.
The formula says that work=force*displacement.
Therefore the work will be zero if displacement is zero
90
45
It has only magnitude and no direction. It depends on magnitude of two vectors which are multiplying and cosine of angle between them. A . B = AB (cosine of angle between them). Best example is 'work done by a force' = force . displacement = Fd(cosine of angle between force and displacement)
You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry. ======================== Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
The angle between 2 vectors can have any value.
angular displacement is a vector quantity when theta (angle) is small, otherwise it is scalar.
45
If the angle between the displacement and force applied is less than a right angle, then it is Positive Work done. If the angle between the displacement and the force applied is greater than a right angle then it is Negative Work done. If the displacement and force are at right angles, or either is zero, then it is Zero Work done.
Work = Force * displacement if the displacement and the force are parallel - work is positive if force and displacement are in the same direction, negative if they have opposite direction. At an angle Work = Force * displacement * cos(θ) where θ is the angle between the force and displacement vectors.
It has only magnitude and no direction. It depends on magnitude of two vectors which are multiplying and cosine of angle between them. A . B = AB (cosine of angle between them). Best example is 'work done by a force' = force . displacement = Fd(cosine of angle between force and displacement)
You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry. ======================== Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
amplitude
it is the dot product of displacement and force . i.e. Fdcos(A) where F is the magnitude of force , d is the magnitude of displacement and A is the angle between them
Any distance between 3m and 15m, depending on the angle between the two individual displacements.
pythagorean theorem
The question cannot be answered. i72 metres is a measure of linear displacement or distance whereas an angle is angular displacement. An angle is measured in degrees or radians, not units of length. If you extend the arms of the angle, the legnth between their ends will increase! Same angle, different length.
You are mixing up 'phase angle' with 'angular displacement' (or 'phase displacement'); these are two completely different things. The term you should be using is 'angular displacement', which is the angle by which the secondary line voltages lagthe primary line voltages. The '7' indicates that this is 7 times 30 degrees; or 210 degrees.
If the angle between force and displacement is between 90 to 270 degree because value of cosine trignometric function is negative within these limits.work=fdcos(angle)