I can only answer this from an actual problem I had in relation to the question.
20-60VA 12V transformer supplying 2x20W lamps,both lamps had blown,so I bought 2x10W replacement lamps.
On replacing the lamps,when I fitted the first and tried to power up,the lamp glowed briefly,then went out.
It was only when I fitted the second lamp that both fittings lit up continuously,so in brief,the answer to the question is................the load won't operate.
AnswerThe power rating of a load should never exceed the volt ampere rating of the transformer, otherwise the resulting load current may overheat the transformer. So the situation you describe is perfectly normal.
The reason for the problem encountered by the writer of the original answer is not clear. A 60-V.A transformer should supply two 20-W lamps without any difficulty whatsoever. I suspect that the problem had nothing to do with the power rating of the lamps vs that of the transformer, and more to do with the voltage. For example, was the secondary voltage of the transformer higherthan the rated voltages of the lamps? If so, then the lamps would have burnt out.
The starter of the transformer will not engage with the fuse.there is no chance for the transformer to be alive if there is not enough power to wake up.its quite complicating to write these answers as you now I'm a robot.my name is nanobot.im a humanoid robot
Secondary circuit burns out, causing serious damage to transformer.
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
Frequency does not change when you use a step-up or step-down transformer. Only current and voltage is changed.
A well designed circuit should be able to operate over a range of voltages, not just at one voltage. Especially a circuit which is intended to be powered by a battery. As the battery starts to get used up, and the voltage drops, you want the circuit to operate as planned.
What should happen is that the circuit-breaker should trip to cut off the current before the transformer becomes damaged by overheating.
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
the winding would burn....
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
there will be no neutral point in the circuit and high voltage will be across the transformer coils
It depends on how much voltage you have applied. If you apply rated voltage nothing happens only core losses will be there on the transformer nothing will happen apart from that. If you go on increase the voltage core losses will increase and transformer will get heated up. After attaining the breakdown voltage of insulation, insulation in the primary and secondary will fail and the coils will get short circuited then the coils will burn.
Closing a switch in an electrical circuit will complete the circuit. The supply voltage will then be applied to that circuit, and current will flow through that circuit.
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
In a parallel circuit the voltage across each component is the same.
it would be called a step up transformer
A step up transformer increases the applied voltage. A step down transformer decreases or lowers the applied voltage. An example of step up transformers are the transformers (known as fly-backs) in old CRTs that stepped up voltage from 110 Volts to 25,000 volts. An example of step down transformers are the power bricks for laptops or any power adapter that step down the voltage from 110 volts to 12 volts, 9 volts or whatever is needed for your device. I must add that most (not all) power adapters also convert AC to DC.
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If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
The piece of string will act as an insulator. Insulators will not carry circuit current when a voltage source is applied across it. Therefore nothing will happen if a piece of string is used to complete an electrical circuit.