You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
When resistors are wired in series, their resistances are added to find the total resistance. If they are run in parallel, or series-parallel, the formula is different
Add the two together. For instance, two 100 ohm resistors in series have a total resistance of 200 ohms.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
You add the resistances together to get the total resistance in a series circuit. Say... R1=10 R2=12 R3=10 R123=32
i dont know the aswer, please answer
If they are in series, you need to add the resistance values.
Resistors are wired in series when they are connected in a line. The current flows through the resistors one after the other.
I observe that the total effective resistance of several resistors in series is the sum of the individual resistance values of the individual resistors.
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
The total resistance of resistors in series is simply the sum of the resistance values of those resistors. If the resistors are identical, then you can multiply the resistance of one of them by the number of resistors in the circuit.
In a series circuit, just add all the individual resistances, to get the total resistance.
When capacitors are connected in parallel, the total capacitance in the circuit in which they are connected is the sum of both capacitances. Capacitors in parallel add like resistors in series, while capacitors in series add like resistors in parallel.