If they are in series, you need to add the resistance values.
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
50 ohms
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.
There is no 'equivalent resistance' for three resistors connected in star.
400 ohms
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
30 ohms
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
28 + 56 = 84 ohms
50 ohms
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
Resistors placed in series create a total resistance that is found by simply adding the values of the resistors. (Knowing the applied voltage isn't necessary to solve this problem.) Rt = R1 + R2 + R3 = 2 ohms + 4 ohms + 6 ohms = 12 ohms
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
The combined resistance is 7.6049 ohms.