B forms 3 bonds (has 3 valence electrons) and is sp2 hybridized, so the molecule is trigonal planar, which is symmetrical. P can form 5 bonds (has 5 valence electrons), and in PCl3 has a free electron pair which makes the molecule non-symmetrical.
The geometry of PCl3 is trigonal pyramidal. As a result the more electronegative chlorine atoms pull the electrons away from the phosphorus in a net direction.
The geometry of BCl3 is trigonal planar. So the three B-Cl bonds are evenly spaced in the same plane. As a result, the polarity of the bonds essentially cancel each other out.
dipole-dipole
No,pcl3 has one lone pair and three bonded pair , shape of trigonal pyramidal with a bond angle of 107 degrees whereas bcl3 has 3 bonded pairs and no lone pairs , shape of trigonal planar with the bond angle of 120 degrees.
NH3 is not symmetrical.So it has a dipole moment
NH3 is an asymmetrical compound.So it is exhibits.
no dipole moment
dipole-dipole
No,pcl3 has one lone pair and three bonded pair , shape of trigonal pyramidal with a bond angle of 107 degrees whereas bcl3 has 3 bonded pairs and no lone pairs , shape of trigonal planar with the bond angle of 120 degrees.
NH3 is not symmetrical.So it has a dipole moment
NH3 is an asymmetrical compound.So it is exhibits.
The dipole moment of Glucose is 1.8
no dipole moment
what is dipole moment of 1,1-Dibromoethene
N2O has a dipole moment of 0.166 D
KrF2 is a linear molecule and therefore there is no dipole moment.
because dipole moment depends upon charge i.e. electronegativity as per the formula of dipole moment
BCl3 is non-polar. The B-Cl bonds are polar but the molecule is not. You should review shapes of molecules. Valence Shell Electron Pair Repulsion, VSEPR. Applying VSEPR on BCl3, we can find out that the shape of the molecule is trigonal planar. Due to its geometry, the bonds cancel out.
NH3 is polar compound.So dipole moment is not zero.