The current is proportionately high as heater requires current to heat the filament.The voltage is deliberately low to sustain the safe power consumption limits.
Since power is current times voltage, doubling current while keeping voltage the same will double the power. Ignoring slight non-linearity, if the power doubles, the heat will double.
Yes, there are immersions heaters for vehicles and travel. They are typically used for camping though. I'd be careful using one while driving. http://www.amazon.com/Travel-Immersion-Water-Heater-Voltage/dp/B000AXS0UE
i believe it would be the computer.
When using the Calor Gas heater, the heater must not be moved in any way. One must not put clothes and/or similar equipment directly on the heater while it is in use.
In general, greater voltage will increase the current through any load, and increase the power that it dissipates. For appliances whose primary use of electrical energy is to produce heat ... such as a toaster, percolator, electric stove, steam iron, electric residential water heater or baseboard room heater etc. ... the appliance is electrically just a resistor, and the power it dissipates is just E2/R. So you'll measure power consumption that's nearly proportional to the square of the applied voltage. That's 'nearly', not exactly, because the resistance of the heater element increases somewhat as its temperature increases. But the square of the voltage is still the best approximation. The best way to collect experimental results is to devise and construct an experiment, let it run, make measurements while it's running, observe the final state, and then organize and present your own observations in some appropriate format.
A water heater element will burn out in a mater of seconds if you apply voltage to it while it is not submerged in water.
If, while you're using it, it spontaneously com busts then you might want to replace it.
this happen due to sudden amount of voltage drop in the main feeder due to large current drawn by the heater , so this drop in voltage will let the bulb operate by avltage of a mount (V-Vd) [where V represent the supply voltage and Vd represent the voltage drop in the main feeder of the circuit] , which is less than the voltage before the heater is connected and due to this situation the current passes through the wire of the bulb will be less and therefore the brightness of the bulb becomes dim.after a while the wire of the heater will has high temperature which increase its resistance and due to this the current drawn by the heater will decrease than the current at the first time , therefore the drop in voltage will also decrease , which implise increase in current drawn by the bulb and therefore the dimness decrease .
something to drop the excess voltage across while clipping.
Voltage can be measured using the difference between the potentiel between two ends of wire or by using a volt-meter. You can easily measure volt by volt or multimeter but remember voltage always measure across the components but in parallel
It doesn't, allthough the resistive value is dependant on heater temperature the resistance of the sensor changes due to the presence of certain gasses (methane in this case) while the heater element itself facilitates a catalystic reaction in the sensor element. The temperature of the heating element is self-regulated and dependant on heater voltage.
first we connect the oscilloscope with the function generator or whatever the source of the input voltage , there will be a wave ,we try to adjust its amplitude using oscilloscope ..and this amplitude will be the peak to peak voltage..putting into consideration how volt/ div while measuring the amplitude