Write a program which will read a string and rewrite it in the alphabetical order?

Answer 1

#include<stdio.h>

#include<conio.h>

#include<string.h>

void main(void)

{

int i,k,n;

char name[50],temp;

printf("\n enter no.of persons");

scanf("%d",&n);

for(i=0;i<n;i++)

gets(name[i]);

for(k=0;k<n-1;k++)

{

for(i=0;i<n-k-1;i++)

{

if(strcmp(name[i],name[i+1])>0)

{

strcpy(temp,name[i]);

strcpy(name[i],name[i+1]);

strcpy(name[i+1],temp);

}

}

}

printf("\n sorted list \n");

for(i=0;i<n;++i)

puts(name[i]);

}

Answer 2

#include<stdio.h>

#include<conio.h>

main()

{

char names[40][20],temp[20];

int i,n,j;

printf("How many names?:");

scanf("%d",&n);

printf("Enter the %d names one by one:",n);

for(i=0;i<n;i++)

scanf("%s",names[i]);

for(i=0;i<=n-1;i++)

for(j=i+1;j<n;j++)

if(strcmp(names[i],names[j])>0)

{

strcpy(temp,names[i]);

strcpy(names[i],names[j]);

strcpy(names[j],temp);

}

printf("Names in Alphabetical order");

for(i=0;i<n;i++)

printf("%s",names[i]);

getche();

}

Answer 3

Answer 1This program is for java.

class project_4

{

/*Enter a sentence*/

public static void main(String sent)

{

int i,x,length;

length=sent.length();

char temp;

char ch[]=new char[length];

for(i=0;i

{

ch[i]=sent.charAt(i);

}

for(i=0;i

{

for(x=0;x

{

if(ch[x]>ch[x+1])

{

temp=ch[x];

ch[x]=ch[x+1];

ch[x+1]=temp;

}

}

}

for(i=0;i

System.out.print(ch[i]);

}

}

Answer 2public static final String sort(final String str) {

final char[] chars = str.toCharArray();

Arrays.sort(chars);

return String.valueOf(chars);

}

Answer 3

import java.io.*;

class Alphabetical

{

protected static void main()throws IOException

{

BufferedReader in=new BufferedReader(new InputStreamReader(System.in));

System.out.print("Enter the String: ");

String s=in.readLine();

for(short i=65;i<91;i++)

{

for(short j=0;j

{

char ch=s.charAt(j);

if(ch==i ch==i+32)

System.out.print(ch);

}

Answer 4

// Names are stored here

final ArrayList<String> names = new ArrayList<String>();

// Get input from standard in

final BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

// Prompt for input

System.out.println("Enter names to sort: ");

// Get input

String currentLine;

while ((currentLine = in.readLine()) != null) {

// A blank line equals the end of input

if (currentLine.equals("")) {

break;

}

names.add(currentLine);

}

// Remember to close our input

in.close();

System.out.println("Sorting: " + names);

// Let Java do our sorting for us.

Collections.sort(names);

System.out.println("Sorted: " + names);

Answer 5

public class sort1

{

public static void main(String args[])

{

int len = args.length;

if(len == 0)

{

System.out.println("No Arguments");

System.exit(0);

}

char str[] = args[0].toCharArray();

char temp;

for(int i = 0; i<len ; i++)

{

for(int j = 0; j<len ; j++)

{

if(str.CharAt(j) > str.CharAt(j+1))

{

temp = str[j];

str[j] = str[i];

str[i] = temp;

}

}

}

for(int i = 0 ; i< len; i++)

{

System.out.println(str[i]);

}

}

}

Answer 6

I assume you want to sort the names alphabetically. Java has a built in alphabetical sorting command. You first need to put your strings into an array, and then use the method java.util.Arrays.sort(String Array). The method Collections.sort(List Name) will then sort your list into alphabetical order. Keep in mind you will need to import these methods.

Answer 7

Write a program using a while loop to print the numbers 2 to 10 in increments of two. The output of your program should be 2 4 6 8 10

Answer 8

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