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0.60mol Cu is how many grams?

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Anonymous

14y ago
Updated: 8/16/2019

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How many grams of Cu(NO3)2 will be produced if you start with 4.2 grams of cu?

To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.


How many moles of atoms are in 4.5 grams of Cu?

4,5 moles of copper are equivalent to 285,957 g.


How many moles of copper are present in 75.92 g?

The atomic mass of Copper is 63.5 grams One mole of any element has a mass equal to the atomic mass. 0.75 grams of Cu = x moles of Cu 63.5 grams of Cu = 1 mole of Cu Set up a proportion and solve for x Divide 0.75 / 63.5 = x /1 0.75 ÷ 63.5 = x


How many moles of copper are there in 128 grams of copper?

Multiply 564 grams of copper by 1 mole over the atomic mass of copper (represented in grams). 564 g Cu * 1 mol Cu / (atomic mass) g Cu The atomic mass is located on the periodic table and represented in atomic units. The same value is used here, but with the unit as grams.


How do you convert 2068 grams of copper to moles?

For this you need the atomic mass of Cu. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.2068 grams Cu / (63.5 grams) = 32.6 moles Cu


How many grams of Cu would be needed to react with 2.0 mol HNO3?

The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O. From the equation, it can be seen that 1 mol of Cu reacts with 4 mol of HNO3. Therefore, to react with 2.0 mol of HNO3, 0.5 mol of Cu is needed. The molar mass of Cu is approximately 63.5 g/mol, so 0.5 mol of Cu would be equivalent to 31.75 grams.


Copper will react with silver nitrate to form copper nitrate and silver From this reaction 127.1 grams of copper will produce how many grams of silver?

The balanced equation for the reaction is: Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag Calculate the molar mass of Cu and Ag (Cu = 63.55 g/mol, Ag = 107.87 g/mol). Using the molar ratio of Cu to Ag (1:2), convert the mass of Cu to moles, then use the molar ratio to find the moles of Ag produced. Finally, convert moles of Ag to grams using the molar mass of Ag to find the grams of silver produced.


If you wish to obtain 10.0 grams of copper metal from copperII sulfide what mass of copperII sulfide must you use - A.10.0 grams B.24.6 grams C.607 grams or D.15.0 grams?

B. 24.6 grams. To find this, you must first calculate the molar mass of Cu and CuS. This will give an idea of the mole ratio between Cu and CuS. Then, you can use stoichiometry to determine that 24.6 grams of Cu₂S will yield 10.0 grams of Cu.


Grams of Cu in a 100 g sample of unknown?

your question is incomplete or incorrectly worded You want to know how much copper is in 100 grams of an unknown sample. The unknown could be made of anything, it may not even contain copper. You should include more information in your question


What is the maximum amount of Cu that could be produced by reacting 20.0 grams of Al with excess CuSO4?

find moles: 20.0 grams of Al @ (27.0 g/mol) = 0.7407 moles of Al by the reaction: 2 moles Al+3CuSO4 → Al2(SO4)3 +3 moles Cu 0.7407 moles of Al produces 3/2 's as many moles of Cu = 1.11 moles of Cu find mass, using molar mass: 1.11 moles of Cu @ (63.5 g/mol) = 70.6 grams of Cu your answer is 70.6 g


How many molecules are there in 122 grams of Cu NO3 2?

To determine the number of molecules in 122 grams of Cu(NO3)2, you need to first calculate the number of moles of Cu(NO3)2 using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23) to convert the moles of Cu(NO3)2 to molecules.


Calculate the number of grams 0.345 moles Cu x 63.546 g Cu?

1 mol of an element is equal to it's atomic weight, but with grams instead of amu (or daltons) as the unit. For example, with copper (Cu), 63.5 amu is its rough atomic weight, which means it weighs roughly 63.5g per mol. Then we just need to divide through. 63.5 x 0.345 = 21.9g