15.0
Cu(I) sulfide has the formula Cu2S. Thus the mass in grams of a single formula unit is 63.5 x 2 = 127 for two coppers32.1 x 1 = 32.1 for one STotal = 159.1
There shouldn't be any copper in eight grams of gold! Unless it's a copper/gold alloy.
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
431.5 grams
1654 grams exactly
Cu(I) sulfide has the formula Cu2S. Thus the mass in grams of a single formula unit is 63.5 x 2 = 127 for two coppers32.1 x 1 = 32.1 for one STotal = 159.1
17.9 grams
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
There shouldn't be any copper in eight grams of gold! Unless it's a copper/gold alloy.
431.5 grams
242.594 g
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
Those are 95 percent copper. A US penny weighs 3.11 grams. Of that, 2.9545 grams is copper.
10 grams of copper can kill you. But copper sulphate won't kill you. So don't freak out!
16.3106
35 grams X 80 dollars/ 14 grams = 200. The cost of 35 grams of copper would cost $200 according to the given information.
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.