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What is the mass in grams of a single formula unit of copper(I) sulfide Cu2S?
Wiki User
∙ 6y ago
Cu(I) sulfide has the formula Cu2S. Thus the mass in grams of a single formula unit is 63.5 x 2 = 127 for two coppers
32.1 x 1 = 32.1 for one S
Total = 159.1
Wiki User
∙ 6y ago
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If you wish to obtain 10.0 grams of copper metal from copperII sulfide what mass of copperII sulfide must you use - A.10.0 grams B.24.6 grams C.607 grams or D.15.0 grams?
15.0
What is the mass in grams of a single formula unit of silver chloride?
2.38*10^-22
How many moles are in 300 grams of calcium sulfide?
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
What is the percent of nitrogen in 4.444 moles of ammonium sulfide?
It is important to know that the percent of nitrogen in 4.444 moles of ammonium sulfide is the same as the percent of nitrogen in 454 grams or 4843 moles or 96 kg, etc. Remember the law of definite proportions - chemical compounds always contain the same proportion of elements by mass. Perhaps you were asking how much nitrogen is in 4.444 moles of ammonium sulfide given the percent of nitrogen in any given mass. So we'll do that too: find the percent of nitrogen in any given sample and apply it specifically to 4.444 moles.Before we go directly to the 4.444 moles, we have to figure out how much nitrogen is in any amount of ammonium sulfide by percent. To do this, we need the atomic weights of the elements and add them up to find the total molar mass of the compound.Ammonium sulfide = (NH4)2SNitrogen = 14.0 grams × 2 = 28.0 gramsHydrogen = 1.01 grams × 8 = 8.08 gramsSulfur = 32.1 grams------------------------------------------------------Ammonium sulfide = 68.2 gramsNow we take the mass of nitrogen and divide it by the total mass to get our percent.Nitrogen ÷ Ammonium sulfide = % Nitrogen28.0 grams ÷ 68.2 grams = 0.411 = 41.1% Nitrogen in Ammonium sulfideSince we know that in any amount of Ammonium sulfide contains 41.1% of Nitrogen, we can apply it to the mass given.41.1% of 4.444 moles = .411 × 4.444 = 1.83 moles of Nitrogen in 4.444 moles Ammonium sulfide
When 250. mL of a 0.15 M solution of ammonium sulfide (NH4)2S is poured into 120. mL of a 0.053 M solution of cadmium sulfate CdSO4 how many grams of a yellow precipitate of cadmium sulfide CdS are fo?
0.92g
How many grams of sodium sulfide are formed if 1.90 of hydrogen sulfide is bubbled into a solution containing 2.53 of sodium hydroxide assuming that the sodium sulfide is made in 91.0 yield?
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.
How many grams of iron can be found in a 130 g sample of iron III sulfide?
The formula of iron (III) sulfide is Fe2S3, showing that each formula unit contains two iron atoms. The gram formula unit mass for iron (III) sulfide is 207.87, and the gram atomic mass of iron is 55.847. Therefore, the fraction by mass of iron in iron (III) sulfide is 2(55.847)/207.87 or about 0.5373, and the grams of iron in 130 g of iron (III) sulfide is 0.5373 X 130 or 69.9 grams, to the justified number of significant digits.
What is the formula for potassium hydrogen sulfide?
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
If you wish to obtain 10.0 grams of copper metal from copperII sulfide what mass of copperII sulfide must you use - A.10.0 grams B.24.6 grams C.607 grams or D.15.0 grams?
15.0
How many grams of aluminum hydroxide are obtained from 17.2 grams of aluminum sulfide?
17.9 grams
What is the mass in grams of a single formula unit of silver chloride?
2.38*10^-22
How many moles are in 300 grams of calcium sulfide?
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
Why do you need 40 grams of calcium and 32 grams of sulfur to make 72 grams of calcium sulfide?
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
How many grams are in 2.2 moles of potassium sulfide?
242.594 g
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution?
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
How many grams of aluminum hydroxide are obtained from 15.7 of aluminum sulfide?
16.3106
How many grams are there in 3.3 moles of potassium sulfide?
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
